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Gemiola [76]
3 years ago
11

Which steps allow a user to change the column layout in the Handout Master?

Computers and Technology
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

D. Click the View tab, select Handout Master, and choose the number of columns in the Slides Per Page drop-down list.

Explanation: correctEdg

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Gimme Shelter Roofers maintains a file of past customers, including a customer number, name, address, date of job, and price of
gulaghasi [49]

Answer:

Hence the complete implementation of python code that reads two files and merges them together.

def merge_file(past_file_path,proposed_file_path, merged_file_path):

   past_file_contents=load_file(past_file_path)

   proposed_file_contents=load_file(proposed_file_path)

   proposed_customer_name = []

   for row in proposed_file_contents:

       proposed_customer_name.append(row[1])

   with open(merged_file_path,'w') as outputf:

       outputf.write("Customer Number, Customer Name, Address\r\n")

       for row in proposed_file_contents:

           line = str(row[0]) +", " + str(row[1]) + ", " + str(row[2]) +"\r\n"

           outputf.write(line)

       for row in past_file_contents:

           if row[1] in proposed_customer_name:

               continue

           else:

               line = str(row[0]) + ", " + str(row[1]) + ", " + str(row[2]) + "\r\n"

               outputf.write(line)

       print("Files merged successfully!")

# reads the file and returns the content as 2D lists

def load_file(path):

   file_contents = []

   with open(path, 'r') as pastf:

       for line in pastf:

           cells = line.split(",")

           row = []

           for cell in cells:

               if(cell.lower().strip()=="customer number"):

                   break

               else:

                   row.append(cell.strip())

           if  len(row)>0:

               file_contents.append(row)

   return file_contents

past_file_path="F:\\Past Customer.txt"

proposed_file_path="F:\\Proposed Customer.txt"

merged_file_path="F:\\Merged File.txt"

merge_file(past_file_path,proposed_file_path,merged_file_path)

8 0
3 years ago
True or false that computers that are joined together are able to share hardware and software, but not data
kozerog [31]
False computers are able to share hardware and software but not data
8 0
3 years ago
What does xhtml stand for?
igomit [66]
Extensible Hypertext Markup Language.
3 0
3 years ago
Read 2 more answers
Converting raw data into a more meaningful form is called:
White raven [17]
Converting raw data into a more meaningful form is called: processing
8 0
3 years ago
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
3 years ago
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