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snow_lady [41]
3 years ago
10

The music teacher has a list if 128 students who have signed up for music classes. The music teacher can register 6 students in

each class. What is the LEAST number of classes needed for all the students to be registered in a class?
Mathematics
2 answers:
salantis [7]3 years ago
6 0
The least number of classes needed for all the students to be registered in a class is 21 classes. 
bixtya [17]3 years ago
5 0
128 divided by 6 is 21.3 so you will need at least 22 classes.
You might be interested in
Can you help me please ?
rewona [7]

1.

(Create a table then plot the points)


X | 0 | 1 | 2 | 3 |

-------------------------

Y | -1 | 3 | 7 | 11 |


4 (0) -1 => 0 - 1 = -1

4 (1) -1 => 4 - 1 = 3

4 (2) -1 => 8 - 1 = 7

4 (3) -1 => 12 - 1 = 11


Just apply the table method to the others and you should be fine! :)

8 0
3 years ago
What is the answer for 65=2(d+1)+5d?
vladimir1956 [14]

65 = 2(d + 1) + 5d
65 = 2d + 2 + 5d
65 = 7d + 2
63 = 7d
Finally divide by 7.
d = 63 \div 7 = 9
Hence, the answer is d = 9



5 0
3 years ago
Write the sum in sigma notation. 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50
alisha [4.7K]
The sum in sigma notation for the sequence will be as follows:
From
<span>5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50
first term=5
common difference=5
number of terms=10
n=nth term
thus the sum will be:
(i=2 to 10)</span>∑(5(n-1)+5)
8 0
3 years ago
Read 2 more answers
Hey -
Katen [24]

Answer:

4-3=1

8+9=17

7 x 2= 14

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Pls help this is pretty urgent
KIM [24]

Answer:

(a)  0

(b)  f(x) = g(x)

(c)  See below.

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{x^2+2x+1}{x^2-1}

<u>Part (a)</u>

Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}

Substitute x = -1 to find the limit:

\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0

Therefore:

\displaystyle \lim_{x \to -1}f(x)=0

<u>Part (b)</u>

From part (a), we can see that the simplified function f(x) is the same as the given function g(x).  Therefore, f(x) = g(x).

<u>Part (c)</u>

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero).  Therefore, the quotient approaches infinity.

\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty

5 0
1 year ago
Read 2 more answers
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