Q). The sum of four consecutive natural numbers is 166. What are the numbers?

Mathematics

2 answers:

MariettaO [177]2 years ago

7 0

Answer:

see that attachment

I hope it's help you

Oduvanchick [21]2 years ago

5 0

Let the four consecutive natural numbers are X,X+1,X+2,X+3

Their sum = X+X+1+X+2+X+3 = 4X+6

According to the given problem

Their sum = 166

⇛ 4X+6 = 166

⇛4X = 166-6

⇛4X = 160

⇛X = 160/4

∴ X = 40

X+1 = 40+1 = 41

X+2 = 40+2 = 42

X+3 = 40+3 = 43

The four consecutive natural numbers are 40,41,42,43

also read similar questions: The sum of two prime numbers is 85, what is the product of these two prime numbers? A. 85 B. 91 C. 115 D. 166

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The lengths of the diagonals of a rhombus are 4x and 8x. What algebraic expression gives the perimeter of the rhombus?

Marizza181 [45]

Answer:

Approximately 17.88x or $8x\sqrt{5}$

Step-by-step explanation:

Use pythagorean formula. In a rhombus the diagonals bisect each other and they are perpendicular, so you could have a right triangle with legs of 2x and 4x, the hypoteneuse would then be $\sqrt{(2x)^{2} +(4x)^{2} }= \sqrt{4x^{2} +16x^{2}}$ which is approximately 4.47x. In a rhombus all 4 sides are the same, so multiply that by 4 and you get the perimeter. 4(4.47x) = 17.88x or if you simplify the radical instead it's $8x\sqrt{5}$