Answer:
4 +30/w . . . . for any w≠0
Step-by-step explanation:
The given constraints resolve to 2 equations in 4 unknowns. There are an infinite number of solutions.
The ratio requirement means ...
(x -y +z)/2 = (y -z +2w)/3 = (2x +z -10)/5
Considering the first equality, we can multiply by 6 and subtract the right side.
3(x -y +z) -2(y -z +2w) = 0 ⇒ 3x -5y +5z -4w = 0
Considering the first and last expressions, we can multiply by 10 and subtract the right side.
5(x -y +z) -2(2x +z -10) = 0 ⇒ x -5y +3z = -20
These two equations have solutions ...
x = 10 -z +2w
y = 6 + 0.4z +0.4w
Using these expressions in the ratio of interest, we have ...
(3x +3z -2w) : w = (3(10 -z +2w) +3z -2w) : w = (30 -3z +6w +3z -2w) : w
= (30 +4w) : w
Expressed as a mixed number, the ratio of interest is ...
(30 +4w)/w = 4 +30/w . . . . an infinite number of solutions
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For positive values of w that are divisors of 30, there are 8 possible values:
(w, ratio) = (1, 34), (2, 19), (3, 14), (5, 10), (6, 9), (10, 7), (15, 6), (30, 5)
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<em>Check</em>
It might be interesting to substitute the expressions for x and y into our original equation(s).
(x -y +z)/2 = ((10 -z +2w) -(6 +0.4z +0.4w) +z)/2 = (2 -0.2z +0.8w)
(y -z +2w)/3 = ((6 +0.4z +0.4w) -z +2w)/3 = (2 -0.2z +0.8w)
(2x +z -10)/5 = (2(10 -z +2w) +z -10)/5 = (2 -0.2z +0.8w)
All of these expressions are identical, as they should be.
