All categories

3 years ago

(x - y + z) : (y - z + 2w) : (2x + z - 10) = 2:3:5 Then ( 3x + 3z - 2w) : w = ?pgvzcmckyc?

Mathematics

2 answers:

sukhopar [10]3 years ago

6 0

Answer:

Step-by-step explanation:

in question given ,x = 2, y = 3, z = 5 in this way

(3x+3z+2w) and find the value of w . according to given values and put

Dahasolnce [82]3 years ago

6 0

Answer:

4 +30/w . . . . for any w≠0

Step-by-step explanation:

The given constraints resolve to 2 equations in 4 unknowns. There are an infinite number of solutions.

The ratio requirement means ...

(x -y +z)/2 = (y -z +2w)/3 = (2x +z -10)/5

Considering the first equality, we can multiply by 6 and subtract the right side.

3(x -y +z) -2(y -z +2w) = 0 ⇒ 3x -5y +5z -4w = 0

Considering the first and last expressions, we can multiply by 10 and subtract the right side.

5(x -y +z) -2(2x +z -10) = 0 ⇒ x -5y +3z = -20

These two equations have solutions ...

x = 10 -z +2w

y = 6 + 0.4z +0.4w

Using these expressions in the ratio of interest, we have ...

(3x +3z -2w) : w = (3(10 -z +2w) +3z -2w) : w = (30 -3z +6w +3z -2w) : w

= (30 +4w) : w

Expressed as a mixed number, the ratio of interest is ...

(30 +4w)/w = 4 +30/w . . . . an infinite number of solutions

For positive values of w that are divisors of 30, there are 8 possible values:

(w, ratio) = (1, 34), (2, 19), (3, 14), (5, 10), (6, 9), (10, 7), (15, 6), (30, 5)

_____

Check

It might be interesting to substitute the expressions for x and y into our original equation(s).

(x -y +z)/2 = ((10 -z +2w) -(6 +0.4z +0.4w) +z)/2 = (2 -0.2z +0.8w)

(y -z +2w)/3 = ((6 +0.4z +0.4w) -z +2w)/3 = (2 -0.2z +0.8w)

(2x +z -10)/5 = (2(10 -z +2w) +z -10)/5 = (2 -0.2z +0.8w)

All of these expressions are identical, as they should be.

You might be interested in

Two people bought gas .Each gallon of gas cost the same amount.The money that they spend in dollars is represented by the expres

nata0808 [166]

=75 he bought each person 10

8 0

3 years ago

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

3 years ago

I forgot to add the pic to my last question. Thank you.

docker41 [41]

V= 7x12×?
V=84x?
252÷84=3

4 0

3 years ago

Evquivilent Ratio for 23:37

solong [7]

Answer:

46:74