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2 years ago

Decide wether or not if these are functions

Mathematics

1 answer:

lesantik [10]2 years ago

3 0

Answer:

Relation 1: Not a Function

Relation 2: Not a Function

Relation 3: Function

Relation 4: Not a Function

Explanation:

There can only be one output (what you get out of it) for each input (what you put into the function) in a function.

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What is the slope of the line shown below

Radda [10]

Here's the slope form; (y2- y1) / (x2 - x1)

All you have to do now is just plug in the number into the formula.

(6 - -4) / (6 - 1) = 10/5

Then divide, and the answer is D. 2.

3 0

4 years ago

Read 2 more answers

Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

3 years ago

8x + 4 = 44<br>What is x?<br><br>Test

ale4655 [162]

8x = 44 -4
8x = 40
x = 40/8
x = 5

8 0

3 years ago

Read 2 more answers

Decide if the expression is positive or negative. Explain in words how you know, please.

AysviL [449]

Step-by-step explanation:

The first expression is :

$-11\times \dfrac{2}{3}$

Numerator = -11×2 = -22

Denominator = 3

So, answer will be :

$-11\times \dfrac{2}{3}=\dfrac{-22}{3}$ (negative)

The second expression is:

$-11\times \dfrac{-2}{3}$

Numerator = -11×-2 = 22

Denominator = 3

So, the answer will be :

$-11\times \dfrac{-2}{3}=\dfrac{22}{3}$ (positive)

Hence, this is the required solution.

7 0

2 years ago

If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2 +2x-2). true or false

Mars2501 [29]

If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) this is True.

5 0

3 years ago