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mylen [45]
2 years ago
6

Decide wether or not if these are functions

Mathematics
1 answer:
lesantik [10]2 years ago
3 0

Answer:

Relation 1: Not a Function

Relation 2: Not a Function

Relation 3: Function

Relation 4: Not a Function

Explanation:

There can only be one output (what you get out of it) for each input (what you put into the function) in a function.

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What is the slope of the line shown below
Radda [10]

Here's the slope form; (y2- y1) / (x2 - x1)

All you have to do now is just plug in the number into the formula.

(6 - -4) / (6 - 1) = 10/5

Then divide, and the answer is D. 2.

3 0
4 years ago
Read 2 more answers
Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
8x + 4 = 44<br>What is x?<br><br>Test
ale4655 [162]
8x = 44 -4
8x = 40
x = 40/8
x = 5
8 0
3 years ago
Read 2 more answers
Decide if the expression is positive or negative. Explain in words how you know, please.
AysviL [449]

Step-by-step explanation:

The first expression is :

-11\times \dfrac{2}{3}

Numerator = -11×2 = -22

Denominator = 3

So, answer will be :

-11\times \dfrac{2}{3}=\dfrac{-22}{3} (negative)

The second expression is:

-11\times \dfrac{-2}{3}

Numerator = -11×-2 = 22

Denominator = 3

So, the answer will be :

-11\times \dfrac{-2}{3}=\dfrac{22}{3} (positive)

Hence, this is the required solution.

7 0
2 years ago
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2 +2x-2). true or false
Mars2501 [29]
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) this is True. 
5 0
3 years ago
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