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3 years ago

Question 2

Mathematics

1 answer:

stellarik [79]3 years ago

8 0

To make line AB perpendicular to line CD move point B until the angle between the lines, angle BEC measures 90°.

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A rectangle has a perimeter of 144 inches. The width of the rectangle is 12 inches less than the length. What is the width, in i

mrs_skeptik [129]

The width in inches would be 12, because of the formula:

length x width = perimeter

so you would do it reverse!

perimeter/length = width

so, 144/12 = 12

7 0

3 years ago

Read 2 more answers

The manufacturer of banjos spends $250 to make each banjo and sells them for $400. The manufacturer also has fixed costs each mo

raketka [301]

Answer:

The cost for making x banjos is c = $ 400 x

Step-by-step explanation:

Given as :

The making cost of each banjos = $ 250

The selling cost of each banjo = $ 400

Let The cost for making x banjos = c

Now,

∵ For making 1 banjos , the making cost = $ 250

∴ For making x banjos , the making cost = $ 250 × x

Again,

∵ The selling price of 1 banjos = $ 400

∴ The selling price of x banjos = = $ 400 × x

Hence The cost for making x banjos is c = $ 400 x . Answer

5 0

3 years ago

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Which choice is similar to the figure shown?

IRINA_888 [86]

Answer:

The parallelogram whose sides are 5 and 20 is similar

Step-by-step explanation:

The parallelogram whose sides are 5 and 20 is similar to the given parallelogram whose sides are 2 and 8 because the figures are the same shade and corresponding sides are proportional.

$\frac{2}{5} = \frac{8}{20}$ $\frac{2}{4} \neq \frac{8}{18}$

$\frac{2}{5} =\frac{2}{5}$ $\frac{2}{4} \neq \frac{8}{4}$

8 0

2 years ago

Solve 3(x + 1) + 6 = 33. <br> Plz

Hitman42 [59]

Answer:

The answer is b.

Step-by-step explanation:

Just substitute it. :)

3(8+1)+6=33

8+1=9

9*3=27

27+6=33

3 0

3 years ago

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An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

7 0

3 years ago