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3 years ago

Can you please help with this?:)

Mathematics

1 answer:

zvonat [6]3 years ago

5 0

Answer:

The two lines are neither parallel nor perpendicular

Step-by-step explanation:

Generally, we have the equation of a straight line as;

y = mx + b

where m is the slope of the line and b is the y intercept of the line

Now, we express the two given equations in this form

We have this as;

7y = x + 5

y = 1/7(x) + 5/7

For the second equation, we have;

y = 7x - 4; this is already expressed

the slope of the first line is 1/7

the slope of the second line is 7

when two lines are parallel, their slopes are equal

when two lines are perpendicular, the product of their slopes is -1

As we can see, both cases does not occur in this system of equations

So, we can conclude that both lines are neither parallel nor perpendicular

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2 years ago

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anygoal [31]

Answer:

$0.00851=8.51\times 10^{-3}$ cm.

Step-by-step explanation:

We have been given that the average human body cell is about $5.1\times10^{-4}$ cm in diameter. The diameter of a plant cell is $8\times10^{-3}$ cm.

To find the combined diameter of the body cell and plant cell, we will add both diameters.

First of all let us convert our given diameters in standard notation.

$5.1\times10^{-4}=0.00051$

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$\text{The combined diameter of body cell and plant cell}=0.00051+0.008$

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Let us convert our answer in scientific notation.

$\text{The combined diameter of body cell and plant cell}=8.51\times 10^{-3}$

Therefore, the combined diameter of the body cell and plant cell is $0.00851=8.51\times 10^{-3}$ cm.

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3 years ago

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Ocean tides can be modeled by a sinusoidal function. Suppose that there is a low and high tide every 12 hours, and that high tid

USPshnik [31]

Answer:

(a) $y=5sin(\frac{\pi}{6}(x+2))+5$

(b) 7.5ft above the low tide.

Step-by-step explanation:

(a) To find the function that computes the height of the tide, you need to select the form of the sinusoidal function. For example, use the form:

$y=Asin(B(x-C))+D$

Where A is the amplitude, B the frequency, C the phase shift and D the vertical shift.

The amplitude is half the distance between the highest and the lowest tide:

$A=10/2=5ft$

The frequency is related to the period T by:

$B=\frac{2\pi}{T}$

The period is 12 hours, then

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$B(x-C)=\frac{\pi}{2}\\\frac{\pi}{6}(1-C)=\frac{\pi}{2}\\\frac{1}{6}(1-C)=\frac{1}{2}\\(1-C)=\frac{6}{2}\\-C=3-1\\C=-2$

The vertical shift is the sum of the lowest value, the height of the low tide ( $lt$ ) and the amplitude:

$D=5+lt$

The function is:

$y=5sin(\frac{\pi}{6} (x+2))+5+lt$

Because the function must be the height above low tide height, subtract this heigh from the function:

$y=5sin(\frac{\pi}{6} (x+2))+5+lt-lt$

$y=5sin(\frac{\pi}{6} (x+2))+5$

(b) Use x=11 in the function

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Answer:

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