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2 years ago

Find the area of the figure.7cm8cm11cmArea is ___ square cm?

Mathematics

2 answers:

Vlad [161]2 years ago

6 0

Answer:

616cm³

Step-by-step explanation:

you just need to multiply those numbers

7 x 8 x 11= 616

djverab [1.8K]2 years ago

4 0

$\text{Perimeter of the triangle,}\\\\ 2s = 7 + 8 +11 =26}\\\\\\\implies s = \dfrac{26}2 = 13\\\\\\\text{Apply Heron's formula to find the area of the triangle,}\\\\A = \sqrt{s(s-8)(s-7)(s-11)}\\\\\implies A = \sqrt{13(13-8)(13-7)(13-11)}\\\\\implies A = \sqrt{780} \\\\\implies A = 27.93~~ \text{cm}^2$

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What are the solutions to the quadratic equation (5y + 6)2 = 24?

nata0808 [166]

Answer:

see explanation

Step-by-step explanation:

Given

(5y + 6)² = 24 ( take the square root of both sides )

5y + 6 = ± $\sqrt{24}$ = ± 2 $\sqrt{6}$ ( subtract 6 from both sides )

5y = - 6 ± 2 $\sqrt{6}$ ( divide both sides by 5 )

y = $\frac{-6+2\sqrt{6} }{5}$ and y = $\frac{-6-2\sqrt{6} }{5}$

3 0

3 years ago

What is the value of the missing angle (x+15)

Luden [163]

Answer:

x = 70

Step-by-step explanation:

The total interior angle in a square, even with not a perfect square, adds to 360

Set your formula up as

360 = (x+15) + x + 115 + 90

360 - 115 - 90 - 15 = 2x

140 = 2x

140/2 = x

70 = x

4 0

3 years ago

What are the coordinates of the y-intercept of the line who's equation is 12x + 13y =8???

Ierofanga [76]

Answer:

y-intercept = (0, $\frac{8}{13}$ ).

Step-by-step explanation:

Given the linear equation in standard form, 12x + 13y = 8:

We must transform this equation into slope-intercept form to make it easier to determine the coordinates of the y-intercept.

12x + 13y = 8

Subtract 12x from both sides:

12x + 13y - 12x = - 12x + 8

13y = - 12x + 8

Next, divide both sides of the equation by 13 to solve for y:

$\frac{13y}{13} = \frac{-12x + 8}{13}$

$y = \frac{-12x + 8}{13}$ or $y = -\frac{12}{13} x + \frac{8}{13}$

Next, to determine the y-intercept, we must set x = 0 (because the y-intercept is the point where the graph of the linear equation crosses the y-axis).

Let x = 0:

$y = -\frac{12}{13} x + \frac{8}{13}$

$y = -\frac{12}{13} (0) + \frac{8}{13}$