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2 years ago

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Rebecca draws a graph of a real-world relationship that turns out to be a set of unconnected points. Can the relationship be lin

ear? Can it be proportional? Complete the explanation of your reasoning.

1 answer:

nlexa [21]2 years ago

6 0

Answer:

Step-by-step explanation:

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Find the area of the figure <br> 9 mm

Irina-Kira [14]

Answer:

pi×4.5 ×4.5= 63.64 i hope this helped

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3 years ago

What is 1.008 in a fraction

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4 years ago

the value of k so that the line Containing the points (-8,k) and (-4,-8) is perpendicular) to the line containing the points (10

In-s [12.5K]

Answer:

$k= \frac{-34}{3}$

Step-by-step explanation:

<u>Step 1 :</u>-

<u>Perpendicular condition :-</u>

<u>Step 1:-</u>

Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

$m_{2} = \frac{-1}{m_{1} }$

$m_{1} m_{2} = -1$

<u>Step 2:-</u>

The given points are (-8,k) and (-4,-8)

$m_{1} = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

finding slope of the first line is $m_{1}$

using formula $m_{1} = \frac{-8-k}{-4+8}$

= $\frac{-8-k}{4}$

finding slope of the second line is $m_{2}$

using formula $m_{2} = \frac{--5+11}{5-10}$

= $\frac{6}{-5}$

<u>Step 3:</u>-

using perpendicular condition

The two lines are perpendicular and their slopes are

$m_{1} m_{2} = -1$

$(\frac{-k-8}{4} )(\frac{-6}{5} )= -1$

simplification,we get solution is

$\frac{6(k+8)}{20} =-1$

$6 k+48 =-20$

$6 k = -20 -48$

$6 k = -68$

$\frac{-68}{6}$

$k= \frac{-34}{3}$

<u>Final answer is </u>

$k= \frac{-34}{3}$

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3 years ago

HELP ASAP !!11!!1111!!!

yawa3891 [41]

I would say the answer is the first option. Usually when it asks for opposites, it wants something like the opposite of 15 is -15. Putting a negative on the outside means you solve the same, but you just add a negative sign on the number,

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3 years ago

Read 2 more answers

8x-5y=-118x−5y=−118, x, minus, 5, y, equals, minus, 11 xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis yyy

ZanzabumX [31]

Given:

The equation is

$8x-5y=-11$

To find:

The x-intercept and y-intercept of the given equation.

Solution:

We have,

$8x-5y=-11$

For x-intercept, y=0.

$8x-5(0)=-11$

$8x=-11$

$x=-\dfrac{11}{8}$

$x=-1.375$

So, the x-intercept is at point (-1.375,0).

For y-intercept, x=0.

$8(0)-5y=-11$

$-5y=-11$

$y=\dfrac{-11}{-5}$

$y=2.2$

So, the y-intercept is at point (0,2.2).

3 0

4 years ago