I came up with d and e as an answer
Using the z-distribution, as we are working with a proportion, it is found that the margin of error for the 90% confidence interval is of 0.0524 = 5.24%.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
The margin of error is given by:

In this problem, the critical value is given as z = 1.645, and since 26 out of 80 students said they would be willing to pay extra:

Then, the <em>margin of error</em> is of:

More can be learned about the z-distribution at brainly.com/question/25890103
Answer: x=0,7
Step-by-step explanation:
The 95% margin of error simony states that there is a 95% probability that the confidence interval contains the true population mean.
<h3>What is a margin of error?</h3>
It should be noted that the margin of error simply means a measurement that accounts for the difference between the actual result and the projected result in a survey sample.
In this case, the 95% margin of error simply states that there is a 95% probability that the confidence interval contains the true population mean. This is the radius of the 95% confidence interval.
Learn more about margin of error on:
brainly.com/question/27909412
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Answer:
50 divided by 8 is the best estimation. gives you 6.25