How do you find a missing angle of a triangle using sine cosine and tangent

1 answer:

4 0

There is a math trick my teacher taught me called SOH CAH TOA.

That is an acronym for Sin, Opposite over Hypotenuse. Cosine, Adjacent over Hypotenuse, Tan, Opposite over Adjacent.

Sin: To find Sin, you divide the opposite side of the missing angle by the Hypotenuse.

Repeat the process for the other two.

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Find m(NMP) and m(MPO)

sineoko [7]

Answer:

see explanation

Step-by-step explanation:

Since lines a and b are parallel, then

∠NMP and ∠MPQ are same side interior angles and are supplementary, thus

a + a - 20 = 180

2a - 20 = 180 ( add 20 to both sides )

2a = 200 ( divide both sides by 2 )

a = 100, hence

∠NMP = a = 100° and

∠MPQ = a - 20 = 100 - 20 = 80°

6 0

3 years ago

I'm sorry but these are the multiple choice answers.

Sunny_sXe [5.5K]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array}&
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &200\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, four quarters}
\end{array}\to &4\\

t=years\to &12
\end{cases}
\\\\\\
A=200\left[ \cfrac{\left( 1+\frac{0.07}{4} \right)^{4\cdot 12}-1}{\frac{0.07}{4}} \right]$

7 0

3 years ago

2 triangles are shown. The second triangle is rotated 90 degrees to the right. A point is between both triangles.

Semmy [17]

Answer:

Its center of rotation

Step-by-step explanation:

got it on edge.

4 0

3 years ago

Read 2 more answers

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