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3 years ago

Find the future value and interest earned if $8906.54 is invested for 9 years at 6% compounded continuously

1 answer:

4 0

To find the future value the formula is
A=p e^rt
A future value?
P present value 8906.54
R interest rate 0.06
T time 9 years
E constant
A=8,906.54×e^(0.06×9)
A=15,283.68

To find the interest earned the formula is
I=A-p
I=15,283.68−8,906.54
I=6,377.14

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vesna_86 [32]

Answer:

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Step-by-step explanation:

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3 years ago

The doctor recommended that Mike increase the number of calories he burns working out from 1,500 to 1,800. By what percent did t

Viefleur [7K]

Answer: The number of calories increased by 20%.

Step-by-step explanation:

Given : The doctor recommended that Mike increase the number of calories he burns working out from 1,500 to 1,800.

Previous number of calories he used to burn = 1,500

Increase in calories = 1800-1500=300

Now , the percent increase in calories = $\dfrac{\text{Increase in calories}}{\text{previous calories}}\times100$

$=\dfrac{300}{1500}\times100=20\%$

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3 years ago

A local little league has a total of 90 players of whom 20% are left-handed. How many left-handed players are there? Please help

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18

First you want to change the 20% into a decimal which is .20
Next you want to multiply 90 by .20 because that will give you the answer for 20% of 90
90x.20=18

Hope that helps

7 0

3 years ago

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timurjin [86]

It’s a blank screen .. what’s the question ?

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3 years ago

The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 13001300

Ket [755]

Answer:

No, there is not enough evidence at the 0.02 level to support the strategist's claim.

Step-by-step explanation:

We are given that a political study took a sample of 1300 voters in the town and found that 57% of the residents favored construction.

And, a political strategist wants to test the claim that the percentage of residents who favor construction is more than 54%, i.e;

Null Hypothesis, $H_0$ : p = 0.54 {means that the percentage of residents who favor construction is 54%}

Alternate Hypothesis, $H_1$ : p > 0.54 {means that the percentage of residents who favor construction is more than 54%}

The test statistics we will use here is;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }$ ~ N(0,1)

where, p = actual percentage of residents who favor construction = 0.54

$\hat p$ = percentage of residents who favor construction in a sample of

1300 voters = 0.57

n = sample of voters = 1300

So, Test statistics = $\frac{0.57 -0.54}{\sqrt{\frac{0.57(1- 0.57)}{1300} } }$

= 2.185

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the percentage of residents who favor construction is 54% and the strategist's claim is not supported.

4 0

3 years ago