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2 years ago

13

Solve the inequality. 3x + 5 ———- <4 2 x < [?]

1 answer:

astra-53 [7]2 years ago

3 0

Answer:

$x \leqslant 1$

Step-by-step explanation:

first multiply both side by 2 to get rid of the fraction

$3x + 5 \leqslant 4(2)$

$3x + 5 \leqslant 8$

$3x \leqslant 8 - 5$

$3x \leqslant 3$

$x \leqslant 1$

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The length of the hypotenuse of a right triangle is 20 feet. The tangent of one of the acute angles, angle 0, is 1.42. What is t

larisa86 [58]

Answer:

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Step-by-step explanation:

We have been given that the length of the hypotenuse of a right triangle is 20 feet. The tangent of one of the acute angles, angle $\theta$ , is 1.42. We are asked to find the length of the side opposite angle $\theta$ .

We can represent our given information in an equation as:

$\text{tan}(\theta)=1.42$

Now, we will use arctan to solve for theta as:

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Now, we will use sine to solve for opposite side as sine relates opposite side of right triangle with hypotenuse.

$\text{sin}=\frac{\text{Opposite}}{\text{hypotenuse}}$

$\text{sin}(54.85^{\circ})=\frac{\text{Opposite}}{20}$

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Read 2 more answers

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