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2 years ago

Which of the following can cause market failure?

Mathematics

1 answer:

nalin [4]2 years ago

5 0

Answer: C

Step-by-step explanation: not enough information

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Help please I will give points

Romashka [77]

Last one full points try to add and help me out plz

4 0

3 years ago

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Find the average value fave of the function f on the given interval. f() = 5 sec2(/6), 0, 3 2

Inessa05 [86]

Answer:

$f_{ave}$ = ${\frac{10 }{3\pi }$

Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3 $\pi$ /2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

$f_{ave}$ = $\frac{1}{b - a}\int\limits^b_a {f(x)} \, dx$

Now,

Here a = 0, b = $\frac{3\pi }{2}$ , f(x) = $5sec^{2}(\frac{x}{6} )$

Now,

$f_{ave}$ = $\frac{1}{\frac{3\pi }{2} - 0}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx$

= ${\frac{2 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx$

= ${\frac{10 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {sec^2 ({\frac{x}{6} }) } \, dx$

= ${\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ]$

= ${\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ]$

= ${\frac{10 }{3\pi }}[ {1 - 0 } ]$

= ${\frac{10 }{3\pi }$

⇒ $f_{ave}$ = ${\frac{10 }{3\pi }$

3 0

2 years ago

This dosent make since to me help

attashe74 [19]

As far as I can tell, is referring and assuming the ruler doesn't have any fractional values, namely it only has markings with integers.

so in short is asking, what are the two integers that the fractional 5¼ is between?

$\bf \boxed{5}\text{\textemdash\textemdash\textemdash}5\frac{1}{4}\text{\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash}\boxed{6}$

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3 years ago

Solve for X<br> 5x + 2 = 7x – 4

Anna71 [15]

X = -3

I’m not sure if that’s correct but hope that helps :)

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2 years ago

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Arturiano [62]

Answer:

<u>Constant | Variables</u>

A C

B E

D F

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2 years ago