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2 years ago

Please help due tmmr please help

Mathematics

1 answer:

Amanda [17]2 years ago

4 0

Answer:

Leo´s response to the bully is a response of hurt and embarrassment. He seems sad and doesn´t even directly respond to the bullies ,¨several

students were huddled around Leo's desk... he had red rings around his eyes. He looked up at Hannah and said, "Why are people so mean?"

Explanation:

if Leo had posted something mean online the outcome would only have worsened. If it were him in the bullies shoes and the bully in his, the bully wouldve understood how these mean things make people feel.

Leo´s response to the bully is a response of hurt and embarrassment. He seems sad and doesn´t even directly respond to the bullies ,¨several

students were huddled around Leo's desk... he had red rings around his eyes. He looked up at Hannah and said, "Why are people so mean?"

Explanation:

Leo´s response to the bully is a response of hurt and embarrassment. He seems sad and doesn´t even directly respond to the bullies ,¨several

students were huddled around Leo's desk... he had red rings around his eyes. He looked up at Hannah and said, "Why are people so mean?"

Explanation:

Step-by-step explanation:

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Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is

Simora [160]

The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: $A=s^2$
Were
$A$ is the area in square kilometers
$s$ is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so $s=0.9$ . Lets replace that value in our formula to find $A$ :
$A=(0.9)^2$
$A=0.81$

Now, to find the population density of the filed, we are going to use the population density formula: $P_{d}= \frac{I}{A}$
where
$P_{d}$ is the population density in <span>in burrows per square kilometer
</span> $I$ is the number of burrows
$A$ is the are of the field
We know that $I=1980$ and $A=0.81$ , so lets replace those values in our formula:
$P_{d}= \frac{1980}{0.81}$
$P_{d}=2444.4$

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>

5 0

3 years ago

Seven wholes times 2 fifteenths

Margarita [4]

7 x 2/15

7 x 2 = 14

14/15 is your answer

hope this helps

4 0

3 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

4 0

2 years ago

Pasagot po please...........

topjm [15]

Answer:

1) ASA

2) SAS

3) SAS

4) SAS

5) SSS

3 0

3 years ago

For a triangle with the length of its sides of 5/36, 1/3 and 13/36, determine if it is a right triangle?

Anuta_ua [19.1K]

Yes it is. Input the numbers into the pythagorean theorem,

${a}^{2} + {b}^{2} = {c}^{2}$

and if they equal each other it is a right triangle.

8 0

3 years ago