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KIM [24]
3 years ago
11

Can someone teach me how to do this?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
5 0

the formula is a_{1}+(n-1) d

so a_{1} would be the first number in the sequence, which would be 13 in problem 9.

13+(n-1)d

then you put in n, which is 10 (it represents which number in the sequence you're looking for, for example 16 is the second number in the sequence)

13+(10-1)d

then you find the difference between each number, represented by d which in this case is 3

13+(10-1)3

13+(9)3

13+27=

40

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A<br> 100 cm²<br> b<br> 9 cm²<br> c<br> 225 cm²<br> d<br> 28.26 cm²
nasty-shy [4]

Answer:

28.26 cm^2

Step-by-step explanation:

A = (pi)r^2

A = 3.14 * (3 cm)^2

A = 3.14 * 9 cm^2

A = 28.26 cm^2

6 0
3 years ago
Plz help :(
Effectus [21]

Answer:

Step-by-step explanation:

6 0
3 years ago
Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it
TiliK225 [7]

Answer:

\dfrac{9}{25}

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}

Now, the <em>required probability</em> can be found as:

P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }

3 0
3 years ago
49/6 into a mixed number
mote1985 [20]
49/6 into a mixed number would be 8 1/6. This is because you would see how many times 6 can go into 49. Since 6 times 8= 48, you subtract that from 49. You are left with one. You put the number you multiplied 6 by as the whole number and the leftover one over six. I hope this helps!
4 0
4 years ago
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Komok [63]
No regrouping: 4.34 + 4.35
Regrouping (carrying): 4.93 + 3.76
6 0
3 years ago
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