AB:BD = 3:4 AC:CD = 3:2 Work out AB:BC:CD
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<u>Answer- </u>Wendy spent 3 hours on the train
<u>Solution-</u>
The distance between the cities= 500 mi.
She traveled part of the way by bus, and other part by train.
The bus averaged 40 mph, and the train averaged 120 mph.
The entire trip took 6.5 hours.
let d = distance traveled by train
the total distance was given as 500 mi ,
therefore, distance traveled by bus = (500-d) mi
time = distance/speed
⇒ train traveling time + bus traveling time = 6.5 hrs
⇒
⇒ d + 3(500-d) = 120(6.5)
⇒ d + 1500 - 3d = 780
⇒ 2d = 720
⇒ d = 360 mi
so d = 360 mi by train
⇒ 360/120 = 3 hrs on the train