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jonny [76]
2 years ago
11

AB:BD = 3:4 AC:CD = 3:2 Work out AB:BC:CD

Mathematics
1 answer:
Papessa [141]2 years ago
5 0

Answer:

15:6:14

Step-by-step explanation:

AB:BD is split into a total of 3+4=7 parts.

AC:CD is split into a total of 3+2=5 parts.

So, if the two ratios are put on a number line together with the points A, B, C, and D, the number line would be split into a total of 35 parts (the LCM of 7 and 5).

AB would be (3/7)*35=15.

CD would be (2/5)*35=14

BC would be 35-(15+14)=6

So, the ratio is 15:6:14.

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Bai is conducting a study on learning. When she manipulates an independent variable, it is possible that some other factor, such
nlexa [21]

Answer:

The answer is : b) a confound

Step-by-step explanation:

While manipulating, is possible that some factors like noise in the hall, can affect learning in one of the groups but not in the other.

This possibility reflects the presence of a confound.

We can define a confounding variable as an external influencing factor which results in bringing changes in the effects of a dependent and independent variable.

This variable changes the outcome of an experiment and produces useless results.

3 0
3 years ago
Erik's disabled sailboat is floating stationary 3 miles east and 2 miles north of Kingston. A ferry leaves Kingston heading towa
sergij07 [2.7K]

Answer:

Step-by-step explanation:

Let's suppose that Ballard is an origin with coordinates (0;0)

Ballard is 8 miles south and 1 mile west of Edmonds ⇒ Edmonds is 1 mile east and 8 miles north of Ballard.

Thus, coordinates of Edmonds (0+1; 0+8) (1;8)

Edmonds is 6 miles due east of Kingston. So, is 6 miles due of Edmonds

Thus, Kingston coordinates (1-6;8) (-5:8)

Sailboat is 3 miles east and 2 miles north of kingston

So, coordinates of sailboat are (-5+3; 8+2) (-2;10)

a)

Ferry leaves Kingston towards Edmonds at mph and Edmonds is 6 miles due east of Kingston.

Initial ferry coordinates as calculated above are equal to Kingston coordinates (-5;8)

After 20 minutes the ferry turns to south.

This distance travelled (20min) is d=9mph*20/60h=3 miles

So, ferry travelled 3 miles toward east in 20 min

Then, coordinates became (-5+3;8+0) (-2;8)

Thus, we have a line connecting two points (-5;8) and (-2;8)

Line connecting them has an equation:

y-8 = (8-8)/(-2+5) * (x+5)

y-8=0

y=8 - This is the equation for the first 20 minutes of travel

Then, ferry turns due south (-2;8) and has a vertiacl line

The equation of verical line is x=a, so the equation will be x=2

b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat.

region looks like a circular disc with a center (-2;10)

(x+2)^2+(y-10)^2=3^2

(x+2)^2+(y-10)^2 <9 (interior of the circular disc)

(x+2)^2+(y-10)^2 >9 (exterior)

The equation of the line joining the Kingston and Edmonds is y=8

the point of intersection:

(x+2)^2+(8-10)^2=9

(x+2)^2=5

x is approximately 0.24; -4.24

(0.24;8) (-4.24;8) - intersection points

c) The ferry exits the radar during the trid due south long x=-2

The points of intersection of the circle and the line x=-2:

(-2+2)^2+(y-10)^2=9

0+(y-10)^2=0

y is 7.13

(-2;7)

d) Takes south turn at (-2;8), then ferry travels 0.8 miles up to point (-2;7) where it exists the radar zone

Speed is 9mph

The time taken to cover 1 mile = t=1/9hr=1/9 *60=6.667min

So, it exists after 6.67 minutes

e) Ferry enters at (-4.24;8) and takes turn due to south at (-2;8)

The distance travelled is = [-4.24+2]=2.24 miles

The time taken to cover these miles is = t=2.24/9 *60=14.93 min

After turning to south ferry remains in radar for 6.7 min

So, it remains in radar zone for 14.93+6.7=21.63min

8 0
2 years ago
I have no clue how to start this problem,plz help
Maksim231197 [3]

9514 1404 393

Answer:

  109°

Step-by-step explanation:

You always start a problem by taking a careful look at the information given and how it relates to what is asked. Here, the key information is in the symbols marking the lines PQ and RS. They are parallel.

This means segments QR and PS are transversals. Marked angle 41° will be an "alternate interior angle" with angle TPQ, so angle TPQ is also 41°.

The desired angle, PTR, is an exterior angle to ΔQTP, so its measure is the sum of remote interior angles TQP (68°) and TPQ (41°). That is, ...

  ∠PTR = ∠TQP +∠TPQ = 68° +41°

  ∠PTR = 109°

6 0
2 years ago
Classify the angles, then find the value of x
marta [7]

Answer:

i dont understand

Step-by-step explanation:

4 0
2 years ago
2/3 + 1/4 what is a simplified expression?
Anna35 [415]

Answer:

11/12

Step-by-step explanation:

We need to get a common denominator of 12

2/3 *4/4 = 8/12

1/4 *3/3 = 3/12

2/3 +1/4

8/12+3/12

11/12

5 0
3 years ago
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