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sweet [91]
2 years ago
13

Nathan hit 19 homeruns. He scored 3 fewer homeruns than twice the number of homeruns hit by jason. Write and solve an equation t

o show how many homeruns Jason hit
Mathematics
1 answer:
Vinvika [58]2 years ago
7 0

Jason hit 11 homeruns.

Step-by-step explanation:

Homeruns hit by Nathan = 19

Let,

Homeruns hit by Nathan = x

Homerun hit by Jason = y

According to given statement;

x = 2y - 3   Eqn 1

We know that Nathan hit 19 homeruns, therefore, putting x=19 in Eqn 1

19=2y-3\\19+3=2y\\22=2y\\2y=22

Dividing both sides by 2;

\frac{2y}{2}=\frac{22}{2}\\y=11

Jason hit 11 homeruns.

Keywords: linear equations, addition

Learn more about linear equations at:

  • brainly.com/question/3375830
  • brainly.com/question/3398261

#LearnwithBrainly

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Lana71 [14]
The answer is -4. The coefficient of a variable is the numerical value directly in front of the variable.
4 0
3 years ago
A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
1 year ago
How do you solve this step by step? “ I’m thinking of a number. If you multiply it by 6 and then add 7, you will get 55. What is
lozanna [386]

Answer:

8

Step-by-step explanation:

55 -7 = 48

48/6= 8

Check answer:

8x6= 48

48+7= 55

5 0
3 years ago
Read 2 more answers
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Hi. I hope this helps!

I believe the answer is 330.26 left.

1. First you add 274 and 144.25

You get 388.25

2. The. You subtract the amount of the video game from 388.25

You get 330.26

I hope this helps! Have a great day!
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victus00 [196]

Answer:

3    

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Step-by-step explanation:

       

                                 10$

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           3$                      3$                    3$

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