Answer:
$7,562.5
Step-by-step explanation:
Given the function of the profit earned expressed as;
<em>f(p) =-40p^2+1100p</em>
To maximize the profit, df(p)/dp must be sero
df(p)/dp = -80p + 1100 = 0
-80p + 1100 = 0
-80p = - 1100
p = 1100/80
p = 13.75
Substitute p = 13.75 into the function
f(13.75) =-40(13.75)^2+1100(13.75)
f(13.75) = -7,562.5+15,125
f(13.75) = 7,562.5
Hence the symphony should charge $7,562.5 to maximize the profit.
Answer:

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.
Step-by-step explanation:
For this case we have that the sample size is n =6
The sample man is defined as :

And we want a normal distribution for the sample mean

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.
So for this case we need to satisfy the following condition:

Because if we find the parameters we got:


And the deviation would be:

And we satisfy the condition:

Answer:
what's the question, what is it asking for??
Answer:
a8=10935
Step-by-step explanation:
A geometric sequece is a sequence of the form

in our case we know that
and
, hence

It is (B) I think:) hope this helps