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dlinn [17]
3 years ago
9

The system of equations n=m and n=4 is the point (0,0). Which of the following statements is true?

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
5 0

Answer:

B.(0,0) is a solution to n=m and to n=4m

Step-by-step explanation:

the system of equations n=m and n=4 is the point (0,0). Which of the following statements is true?

A.)no point on the line is n=m is also on the line n=m

B.)(0,0) is a solution to n=m and to n=4m

C.)The graph of the solution is parallel lines

D.)Every solution to n=m is also a solution to n=4m

(0,0) is a solution to n=m and to n=4m

the solution is the place of intersection between the two lines. they are not parallel and seperate.

The graph attached clearly illustrate that the point of intersection is at (0,0)

(x,y)

let n=y and m represents x

n=m

n=4m

when m=0

n=0, n=0

when m=2

n=2, n=8

at (0,0) the lines meet

babymother [125]3 years ago
3 0
I think but i am not highly sure but it has to be [c]. because if n equals 4 and m then its parallel
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Cheryl is planning to go to a four-year college in two years. She develops a monthly savings plan using the estimates shown. Wha
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3 0
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Step-by-step explanation:

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As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

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Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

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