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Tpy6a [65]
3 years ago
5

What is (- 4/5) - 7/8

Mathematics
1 answer:
mixer [17]3 years ago
5 0

First, find the lowest common multiple of 5 and 8 and it is 40.

So

-32/40 - 35/40

= -67/40

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Plzz anyone answer correctly plz will give brainliest!!
garri49 [273]

Answer: I believe its 3, because its a slope the bottom is the shape of a square witch has all sides equal. therefore each side equals 3

Step-by-step explanation:

3 0
3 years ago
Give a list of three rational numbers, each in a different form. Do not order the numbers.
Mumz [18]

Answer:ddghh

Step-by-step explanation:

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2 years ago
Rebecca supplies costumes to a number of theater companies and recently lent out a number of different hats. turbans 6 berets 3
barxatty [35]

Answer:

3/7

Step-by-step explanation:

Probability a turban is lent = total number of turbans  lent / total number of hats lent

total number of hats lent = 6 + 3 + 3 + 2 = 14

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3 years ago
Decide whether the sequence 4,10,20,34,52 ....... is a linear model,
Alecsey [184]

Answer:

Lineal.

Step-by-step explanation:

To determine if the sequence 4,10,20,34,52 ....... is a linear model, a quadratic model or a cubic model, the following mathematical logical reasoning must be carried out:

4 to 10 = +6

10 to 20 = +10

20 to 34 = +14

34 to 52 = +18

Thus, we can see at a glance that the sequence increases 4 numbers in each digit, adding first 6, then 10, then 14 and so on, with which the next numbers in that sequence should be 74 (+22), 100 ( +26), 130 (+30), 164 (+34), and so on.

Therefore, since there is no quadratic or cubic relationship, the sequence is linear.

6 0
2 years ago
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Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

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Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
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