During anaphase 1 chromosomes in the homologous pair moves to the opposite poles.
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Explanation:</u></h3>
The chromosomes that are having their pairs with similar length, position of centromere and staining pattern refers to the homologous chromosomes. These chromosomes have genes with the corresponding loci. One of these chromosomes will be inherited from the father and the other will be inherited from the mother.
The chromosomes in the pair gets attached to the fibers from the opposite poles. The chromatids that are sister will get attached to the fiber from the same poles. The centromere will not get divided during the anaphase 1 and thus the homologous chromosomes will move to the opposite poles. This causes the homologous chromosomes to get separated.
About the question:
I failed to find the complete question with the Punnett square, so in the answer and explanation I will propose five options for crosses between dogs with different genotypes, and for each option, I will remark the percent of the offspring that is expected to have wirehair. You just need to look for the option that matches your Punnett Square.
Answer:
- Option 1: HH x HH ----> 100% of the progeny is wire-haired, HH
- Option 2: HH x Hh---> 100% of the progeny is wire-haired, HH + Hh
- Option 3: Hh x Hh --->75% of the progeny is wire-haired, 25% HH + 75% Hh
- Option 4: Hh x hh ---> 50% of the progeny is wire-haired, Hh
- Option 5: hh x hh ----> 0% of the progeny is wire-haired
Explanation:
You will find the complete explanation in the attached files due to technical problems
The answer would be letter B.
If the nurse notices that the bag
of TPN solution has been infusing for 24 hours; not minding how much of the
solution is left, the nurse should discontinue the current solution, change the
tubing, and hang a new bag of TPN solution. It is not safe to hang a bag of TPN
for more than 24 hours due to the risk of infection.