What are your answer choices?
Answer:
Jason = <span>20yrs.old</span>
Mandy = <span>15yrs.old</span>
Explanation:
Let
J = Jason's age
M = Mandy's age
<span>J+M=35</span> ..... eq. 1
<span>J−10=2<span>(M−10)</span></span> ..... eq. 2
From eq. 1
<span>J=35−M</span>
Substitute this in eq. 2.
<span><span>(35−M)</span>−10=2<span>(M−10)</span></span>
<span>35−10−M=2M−20</span>
<span>35−10+20=2M+M</span>
<span>45=3M</span>
<span><span>453</span>=<span><span>3M</span>3</span></span>
<span>15=M</span>
<span>J=35−M</span>
<span>J=35−15</span>
<span>J=<span>20</span></span>
Answer:Speculative prediction
Explanation: Speculative prediction is the prediction method which can be optimizing in nature.This method usually runs in such a way that can lead ahead of time by predicting the next step or it's result.
This technique is also known as the dynamic execution which is usually found in the CPU devices and some other modern processing devices.Speculation prediction and execution works even when there is no necessity of the knowing about the next instruction.The result appearing can be correct or incorrect.
The answer is A, B, and C.
D. is too broad a term that actually includes A-C. So in other words there is no company that specializes in "Technology"
There are companies that specialize in E-Commerce, Hardware, and Security.
I guess if you wanted to say Google and Apple are technology companies you could say that but even they would fit into a particular classification. Google would be a Search Engine technology, and Apple would probably still be considered a hardware company even though both companies are involved across all of the 3 subjects in the answer.
Answer:
The program in recursion is:
def find_max(nums):
if len(nums) == 0:
return "None"
elif len(nums) == 1:
return nums[0]
else:
return max(nums[0],find_max(nums[1:]))
Explanation:
This line defines the function
def find_max(nums):
This checks if the list is empty.
if len(nums) == 0:
If yes, it returns "None"
return "None"
If the list has just one element
elif len(nums) == 1:
It returns the only element as the maximum
return nums[0]
If the list has numerous elemente
else:
The maximum is determined recursively
return max(nums[0],find_max(nums[1:]))
To the (b) part:
<em>This program does not necessarily need to be done recursively because the max built-in function can be used to determine the maximum of the list in just one line of code and it is more efficient.</em>
