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3 years ago

Find the value of x and y

1 answer:

8 0

Answer:

x=55 y=62.5

Step-by-step explanation:

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GarryVolchara [31]

Rewrite the limit as

$\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}$

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

$\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}$

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3 years ago

DIA [1.3K]

Step-by-step explanation:

hope it's helpful ❤❤❤❤

THANK YOU

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Brilliant_brown [7]

Answer: Your answer is<u> 3.53</u> as a Decimal.

Hope this helps!

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3 years ago

Vesna [10]

Do you have a photo where I can see your problem?

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3 years ago

lesantik [10]

2sinxcosx is equal to sin(2x)

therefore,

= sin(2x)/cos(2x)
= tan(2x) (ANSWER)

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3 years ago