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ASHA 777 [7]
3 years ago
11

Someone help me with this still im stock on it plz

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

a>4 or a < 8

Step-by-step explanation:

We can start with the inequality on the left

-a + 2(4+3a) > 28

expand using the distributive property

-a + 8 + 6a > 28

5a + 8 > 28

subtract 8 from both sides to isolate the variable and its coefficient

5a > 20

divide both sides by 5 to isolate a

a > 4

moving on to the inequality on the right

2a - (3a+4) > -12

treat the minus sign as a -1

2a + (-1)(3a+4) > - 12

expand

2a - 3a - 4 > - 12

-a - 4 > -12

add 4 to both sides to isolate a and its coefficient

-a > - 8

multiply both sides by -1 but change the sign because we are multiplying by a negative number

a < 8

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Answered by Gauthmath

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3 years ago
After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6, 3), B'(-2, 1),
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Answer:

<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)

Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
  • 180°-rotation >> (x, y) → (-x, -y)

So, perform your rotation:

270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]

→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]

→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]

I am joyous to assist you anytime.

3 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

A=ah+bh+ch+1

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