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2 years ago

Someone help me with this still im stock on it plz

Mathematics

1 answer:

pav-90 [236]2 years ago

5 0

Answer:

a>4 or a < 8

Step-by-step explanation:

We can start with the inequality on the left

-a + 2(4+3a) > 28

expand using the distributive property

-a + 8 + 6a > 28

5a + 8 > 28

subtract 8 from both sides to isolate the variable and its coefficient

5a > 20

divide both sides by 5 to isolate a

a > 4

moving on to the inequality on the right

2a - (3a+4) > -12

treat the minus sign as a -1

2a + (-1)(3a+4) > - 12

expand

2a - 3a - 4 > - 12

-a - 4 > -12

add 4 to both sides to isolate a and its coefficient

-a > - 8

multiply both sides by -1 but change the sign because we are multiplying by a negative number

a < 8

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2 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

First case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

Second case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

Can someone help me with this triangle?? Find missing side lengths

lakkis [162]

Answer:

M= 15 degrees N= 15 degrees

Step-by-step explanation:

Right triangles are always 90 degrees so 90-60=30

since theres 2 sides you have to split 30 in 2 so 30 divided by 2 equals 15

7 0

2 years ago

Solve for x check your solution

abruzzese [7]

Area for a triangle is (1/2) bh or bh/2
So using this info, b = 1.5 m and h = x and A = 1.5 m^2

A = bh/2
1.5 = 1.5x/2
Multiply both sides by 2 to get rid of fraction ... 3 = 1.5x
Divide both sides by 1.5 ... 2 = x so x= 1.5 m

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2 years ago

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kaheart [24]

A unit rate is when it is in simplest form

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2 years ago

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