Answer:
(5, - 2 )
Step-by-step explanation:
Given the 2 equations
9x + 5y = 35 → (1)
- 2x - 5y = 0 → (2)
Adding the 2 equations term by term will eliminate the y- term
7x = 35 ( divide both sides by 7 )
x = 5
Substitute x = 5 into either of the 2 equations for value of y
Substituting in (1) gives
9(5) + 5y = 35
45 + 5y = 35 ( subtract 45 from both sides )
5y = - 10 ( divide both sides by 5 )
y = - 2
Solution is (5, - 2 )
Answer:40 min
Step-by-step explanation:
5+.10x=3+.15x
-.10. -.10
5= 3+.05x
-3. -3
2=.05x
Divide by .05
X=40
Answer:
(0, -3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
x - 4y = 12
x - 5y = 15
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
- Subtract 2 equations: y = -3
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x - 4y = 12
- Substitute in <em>y</em>: x - 4(-3) = 12
- Multiply: x + 12 = 12
- Subtract 12 on both sides: x = 0
I like to start by dividing the given number by 2, unless a larger factor is evident.
1386 = 2(693). It's pretty obvious that we can divide 693 by 3: 693=3(231).
Then we have 1386 = (2)(3)(231). Try the same procedure. Does 231 have any integer, prime factors? See how far you can take this factoring.
The correct answer is 224.
