Two postcards every five days therefore I think it would be 2/5 because rose over run (this may be wrong but that is was I got)
Hello,
log (16)=2 in base 3x-5
==>16=2^(3x-5)
==>2^4=2^(3x-5)
==>4=3x-5
==>3x=9
==>x=3
The slope-intercept form of a line is:
y = mx + b
Where m is the slope and b is the y-intercept.
Two lines having slopes <em>m1</em> and <em>m2</em> are perpendicular if
m1 * m2 = -1
We are given the equation of one line:
![y=\frac{1}{3}x-5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx-5)
It's required to find the equation of another line that is perpendicular to it. We have m1 = 1/3, let's find the other slope:
![\begin{gathered} m_1\cdot m_2=-1 \\ \frac{1}{3}\cdot m_2=-1 \\ Thus\colon \\ m_2=-3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20m_1%5Ccdot%20m_2%3D-1%20%5C%5C%20%5Cfrac%7B1%7D%7B3%7D%5Ccdot%20m_2%3D-1%20%5C%5C%20Thus%5Ccolon%20%5C%5C%20m_2%3D-3%20%5Cend%7Bgathered%7D)
The slope of the required line is -3. Now we use the point through which the line passes (-2, 2).
We use the point-slope form of the line:
y - k = m( x - h)
Where (h,k) = (-2, 2) is the point. Substituting:
![y-2=-3(x+2)](https://tex.z-dn.net/?f=y-2%3D-3%28x%2B2%29)
Operating:
Answer:
141
Step-by-step explanation:
The interior angles of a polygon with <em>n</em> sides is 180(<em>n</em> - 2) and the polygon has 7 sides, so the sum of its interior angles is 180(7 - 2) = 180(5) = 900.
125 + (x + 7) + 107 + (x - 15) + x + 131 + 122 = 900
Combining like terms,
3x + 477 = 900
3x = 423
x = 141
I already answered this question
<span>17 1/3 + (-50 1/3) -5 1/2
= -33 - 5 1/2
= (</span>-33 ) + ( - 5 1/2)
<span>= -38 1/2
</span>= -38.5