Y= 86 degrees and x= 47 degrees
I believe.
So since we know that the post is 40 yards away, plug in 40 into the x variable of the equation to solve. If y is greater than 10 when x = 40, then it made it over. If y is less than 10 when x = 40, then it does not make it over. 
Firstly, solve the exponent: 
Next, solve the multiplications: 
Lastly, solve the addition and your answer will be: 
Since the football was 16 ft high, as opposed to the goal post's 10 ft, when it was at the goal post, it had successfully gone over the post. And since 16 ft is 6 ft higher than 10 ft, the football was 6 ft higher than the goal post when it went over.
Answer:
0.00142857143 km
Step-by-step explanation:
Answer:
The dimensions are 18 * 18 * 36in
Step-by-step explanation:
Let the lengths of the square ends be x in and the length be y in.
Then the maximum length + girth
= 4x + y = 108in
The volume V = x^2y.
From the first equation:
y = 108 - 4x
so V = x^2(108 - 4x)
= 108x^2 - 4x^3
Finding the derivative:
V' = 216x - 12x^2 = 0 ( for a maximum volume).
12x( 18 - x) = 0
x = 18
So the value for x for a maximum volume = 18 in
This gives y = 108 - 4(18) = 36 in.