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user100 [1]
2 years ago
10

What does the 1 represent in 5,149.23

Mathematics
1 answer:
Genrish500 [490]2 years ago
7 0
The 1 represents the hundredth place
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Pearson realize help please!
yulyashka [42]

Answer:

I think it would be 15

Step-by-step explanation:

Because if you split the number line into 6 different sections (with the 15 on the left side and the 16 on the right side) and shade/fill in 2 of those, you would be closer to 15.

6 0
3 years ago
In the right △ABC, CD is the altitude to the hypotenuse AB and m∠ABC=30°. Find AD, if BD=54 cm.
LUCKY_DIMON [66]

The ratios of sides in a 30°-60°-90° triangle are such that the hypotenuse (AB) is double the length of the shortest side (AC). In your triangle, AC is the hypotenuse of similar triangle ACD, which has AD as its shortest side.

Then

... (1/2)×(AD+54) = AC

... (1/2)×AC = AD

Together, these tell you

... AD = (1/4)(AD +54)

... 3×AD = 54

... AD = 18

5 0
3 years ago
Read 2 more answers
A) A shopkeeper marks the price of an article R's. 550 and gives the customer discount of 10℅.In this way, he gains Rs 75 on the
kumpel [21]

Answer:

Marked Price =MP=550 Marked Price =MP=550

Selling Price=SP=550-10%=550-55=495Selling Price=SP=550-10%=550-55=495

The profit earned is , SP−Profit=CP(CostPrice)The profit earned is , SP−Profit=CP(CostPrice)

CP=495−75=420CP=495−75=420

The difference of MP and CP is 550−420=130The difference of MP and CP is 550−420=130

 The percentage of difference w.r.t CP is  The percentage of difference w.r.t CP is 

130420×100=30.95%

Step-by-step explanation:

plz make me as a brainliest

5 0
3 years ago
Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

⇒ 3x=\pm \frac{\pi}{4}

⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

x = \pm cos^{-1}(y)+ 2k\pi

⇒ x = \pm \frac{\pi}{12}+ 2k\pi , k is any integer .

At k=0,

⇒ x =\frac{\pi}{12} ,

At k=1,

⇒ x = - \frac{\pi}{12}+ 2\pi

⇒ x = \frac{23\pi}{12}

Therefore , Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

5 0
3 years ago
Given the table below find f(g(3))
12345 [234]

Answer:

Steps in provided image.

Step-by-step explanation:

5 0
3 years ago
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