v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer: Both A, and C
Step-by-step explanation:
The answer to the first system of equations (2x+2y=16) would be
x=3 and y=5 ( 3x-y=4 )
Which means we have to find out which of the other equations has an x value of 3, and a y value of 5.
If A is 2x+2y=16, then x=3 and y=5
6x-2y=8
If B is x+y=16, then x=5 and y=11
3x-y=4
If C is 2x+2y=16, then x=3 and y=5
6x-2y=8
If D is 6x+6y=48 , then x=-2 and y=10
6x+2y=8
Both A and C are equal to the first system of equations, which means they are both correct answers.
Answer:
x=72 and the exterior angle is 154
Step-by-step explanation:
We will call the unknown angle in the triangle y. Angle y and the angle (2x +10) form a straight line so they make 180 degrees.
y + 2x+10 =180
Solve for y by subtracting 2x+10 from each side.
y + 2x+10 - (2x+10) =180 - (2x+10)
y = 180-2x-10
y = 170-2x
The three angles of a triangle add to 180 degrees
x+ y+ 82 = 180
x+ (170-2x)+82 = 180
Combine like terms
-x +252=180
Subtract 252 from each side
-x+252-252 = 180-252
-x = -72
Multiply each side by -1
-1*-x = -72*-1
x=72
The exterior angle is 2x+10. Substitute x=72 into the equation.
2(72)+10
144+10
154
C: 7/8
Explanation: Since we want a number that makes 4p less than 4, we need to find a number for p that is less than 1. By looking at each fraction, only 7/8 will render it less than 4
What figure , are you trying to figure the volume for
