Question

What is the solution to the inequality |x-4|<3?

Answer 1

|x-4| <3

=>. x-4<3 or -(x-4)<3

=>. x-4<3 or x+4>3

=>. x<7 or x>1

So solution is x>1 & x<7. =x€(1,7)

Hope it helps...

Regards,

Leukonov/Olegion.

Answer 2

Answer:

The solution to the given inequality is:

              $1$ i.e. in the interval form it is given by: (1,7)

Step-by-step explanation:

We are given a inequality in term of variable x as follows:

          $|x-4|$

Now, we know that any inequality with modulus function is opened as follows:

If

$|x-a|$

Then we have:

$-b$

i.e. we may write it as:

$a-b$

Here in the given expression we have:

a=4 and b=3

Hence, the solution is given by:

$4-3$