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Liula [17]
3 years ago
13

You have four quiz grades. Quiz 1: 17/30, Quiz 2: 17/25, Quiz 3: 38/50, Quiz 4: 18/25 What is your ordinary quiz average?

Mathematics
2 answers:
Komok [63]3 years ago
5 0

Answer:

.7 or 70%

Step-by-step explanation:

17/30 + 17/25 + 38/50 + 18/25 = 2.727

2.727 divided by 4 (the amount of addends) = .7

Pani-rosa [81]3 years ago
5 0

Answer:

<u><em>68%</em></u>

Step-by-step explanation:

To find the average quiz grade, you have to add up all the percentages and divide by the numbers of scores you have.

56 + 68 + 76 + 72 = 272

272 ÷ 4 = 68

Hope this helps! <3

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What is mean median mode
Alborosie

Answer:

Step-by-step explanation:

mean- add up all numbers and divide by how many numbers there are

median- the middle number out of the list of numbers

mode- the number you see most often

5 0
3 years ago
Read 2 more answers
PLEASE HELP IMMEDIATELY!!!! Find x when – Negative one-half + x = –Negative StartFraction 21 over 4 EndFraction. – Negative Star
balu736 [363]

Answer:

-61/4

Step-by-step explanation:

-1/2 + x = - 21/4 - 23/4 - 19/4

-1/2 + x = -(21+23+19)/4

x = -63/4 + 1/2

x= -63/4 + 2/4

x = -61/4

Hope that helps, tell me if you need further explanation. =)

3 0
3 years ago
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Jonas’s vacuum cleaner uses 5/8 kilowatts of electricity per hour. His clothes dryer uses 4 11/16 of electricity per hour. How m
alekssr [168]
Hope this helps you out.

6 0
2 years ago
If t(n) = 15 - 2.5n, how do I find t1,t2,t3,and tn+1? I also have to express tn+1-tn in its simplest form.
Anvisha [2.4K]

Answer:

Just substitute, and the simplified form is 1

Step-by-step explanation:

Substitute the values needed into the original equation. For example, if n=1

t(1)=15-2.5(1)=15-2.5=12.5. Or, if tn+1 substitute f(tn+1)=15-2.5(tn+1) and simplify.

tn+1-tn in its simplest form is just 1, as tn and -tn cancel out to leave 1.

8 0
2 years ago
Part A: If (72)x = 1, what is the value of x? Explain your answer. (5 points)
vichka [17]

Answer:

see below

Step-by-step explanation:

Part A:  (72)^x = 1

Take the log base 72 of each side

log72(72^x) = log 72(1)

We know log a^b = b log a

x log72(72) = log72(1)

x =  log72(1)

x = 0

Part A:  (70)^x = 1

Take the log base 70 of each side

log70(70^x) = log70(1)

We know log a^b = b log a

x log70(70) = log70(1)

x =  log70(1)

x = 0

7 0
3 years ago
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