because a midpoint mean middle so A----------M----------B
AM is 1/2 of AB as well as BM is 1/2 of AB
4------------5----------6 if 5 is the midpoint how much is between 4 and 5 and 5 and 6
true is the answer
Explain: it's impossible to divide by 0, so the slope of a vertical line is always undefined. Now consider the y-axis on a graph. The y-axis is the line x = 0, and it is a vertical line. Therefore, all vertical lines, which have undefined slopes, are parallel to the y-axis.
Answer:
140
Step-by-step explanation:
The arithmetic series is 5, 7, 9, 11, ........., 23.
First u have to determine the no. of terms that can be done by using
Tₙ = [a + (n - 1)d]
Tₙ-------nth term
a---------first term
n---------no.of terms in the series
d---------common difference
here a = 5,d = 2.
let it contain n terms Tₙ= [a + (n-1)d]
Substitute Tₙ, a, and d in the equation
23 = 5 + (n - 1)2
Subtract 5 from each side.
18 = (n-1)2
Divide each side by 2
(n - 1) = 9
Add 1 to each side
n = 9 + 1 = 10
The sum of the arithmetic sequence formula: Sₙ= (n/2)[2a+(n-1)d]
Substitute Sₙ, a, n and d in the equation
Sₙ= (10/2)[2(5) + (10-1)2]
Sₙ= (5)[10 + (9)2]
Sₙ= 5[10 + 18]
Sₙ= 5[28] = 140
Therefore the sum of the arithmetic sequence is 140.
The segment addition postulate tells you that
... JK + KL = JL
a) Filling in the given information, you have
... 3n + (5n-7) = 25
... 8n = 32 . . . . . . . . . . . collect terms, add 7
... n = 4 . . . . . . . . . . . . . divide by 8
b) Now, you know that
... JK = 3n = 3·4 = 12
... KL = 5n-7 = 5·4-7 = 13
The segments are: JK = 12; KL = 13.