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2 years ago

What is the answer to this problem 0.05n+0.10(2n)=9.25

Mathematics

1 answer:

kolbaska11 [484]2 years ago

6 0

Answer: n=37

Step-by-step explanation:

0.05n+0.10x2n=9.25

0.25n=9.25

n=9.25/0.25

n=37

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g Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = 7yi + xzj + (

Sati [7]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

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$\vec F(x,y,z)=7y\,\vec\imath+xz\,\vec\jmath+(x+y)\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=(1-x)\,\vec\imath-\vec\jmath+(z-7)\,\vec k$

Take $S$ to be the ellipse that lies in the plane $z=y+9$ with boundary on the cylinder $x^2+y^2=1$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(u\sin v+9)\,\vec k$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath+u\,\vec k$

Then we have

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^1\big((1-u\cos v)\,\vec\imath-\vec\jmath+(u\sin v+2)\,\vec k\big)\cdot\big(-u\,\vec\jmath+u\,\vec k\big)\,\mathrm du\,\mathrm dv$

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5 0

2 years ago

Factor the expression. k2 + 5kf – 50f2

g100num [7]

Answer:

We have

k^2 - 25f^2 + 5kf - 25f^2 =

k^2 - (5f)^2 + 5f( k - 5f) =

( k - 5f )( k + 5f ) + 5f( k - 5f ) =

( k - 5f )( k + 5f + 5f ) =

( k - 5f )( k + 10f );

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Given the equation y − 4 = three fourths(x + 8) in point-slope form, identify the equation of the same line in standard form.

IRINA_888 [86]

Answer:

$3x-4y=-40$

Step-by-step explanation:

The standard form of a linear equation is $ax+by=c$ .

The given line has equation:

$y-4=\frac{3}{4}(x+8)$

This is the point-slope form of the given line.

To find the standard form, we clear the fraction

$4y-16=3(x+8)$

We expand the parenthesis now to get:

$4y-16=3x+24$

We group the variables on the LHS and the constants on the RHS.

$4y-3x=24+16$

$-3x+4y=40$

Multiply through by -1

$3x-4y=-40$

This is of the form: $ax+by=c$ .

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2 years ago

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jarptica [38.1K]

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2 years ago

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snow_tiger [21]

Answer:

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2 years ago