All categories

1 year ago

✎﹏Question~

Mathematics

1 answer:

Varvara68 [4.7K]1 year ago

7 0

Answer:

Sol: In this question, firstly we have to make the first bracket as a complete square of the second bracket. This we can by adding 2.x.1/x which is equivalent to 2. Then the equation becomes:

6(x2 + 1/x2 +2) – 5(x + 1/x) = 50 { 38 + 6*2)

⇒ 6(x2 + 1/x2 +2) – 5(x + 1/x) – 50 = 0

Now put x + 1/x = y

⇒ 6y2 -5y -50 = 0

⇒ (2y +5)(3y-10)= 0

⇒ y=-5/2 or 10/3

As x is positive therefore, x + 1/x =10/3

On solving further you will get as x=3 or 1/3

You might be interested in

Solve the following equation using distribution.

AleksandrR [38]

Answer:

answer is 5.5 on edgen

Step-by-step explanation:

I just solved the problem

7 0

3 years ago

Read 2 more answers

Picture is below...........................

liubo4ka [24]

Answer:

C or A

thats all i know hope it helps

4 0

2 years ago

14. Higher Order Thinking Does Cavalieri's Principle apply to the volumes of the cones shown? Explain

AleksAgata [21]

9514 1404 393

Answer:

yes

Step-by-step explanation:

At each height above the base, the cross section of each cone shown is the same (a circle with the same diameter), so Yes, Cavalieri's Principle applies.

3 0

2 years ago

The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th

Ilia_Sergeevich [38]

Answer:

(0.0757;0.1403)

Step-by-step explanation:

1) Data given and notation

Republicans =115

Democrats=331

Independents=54

Total= n= 115+331+54=500

$\hat p_{ind}=\frac{54}{500}=0.108$

Confidence=0.98=98%

2) Formula to use

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the population proportion is given by this formula

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

We have the proportion of independents calculated

$\hat p_{ind}=\frac{54}{500}=0.108$

We can calculate $\alpha=1-conf=1-0.98=0.02$

And we can find $\alpha/2 =0.02/2=0.01$ , with this value we can find the critical value $z_{\alpha/2}$ using the normal distribution table, excel or a calculator.

On this case $z_{\alpha/2}=2.326$

3) Calculating the interval

And now we can calculate the interval:

$0.108 - 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.0757$

$0.108 + 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.1403$

So the 98% confidence interval for this case would be:

(0.0757;0.1403)

7 0

2 years ago

The formula D= 393t + 5680 can be used to approximate rhe tital average credit card debt in a U.S. household (in dollars) t year

Schach [20]

<span>In this problem the formula for average credit card debt is D=393t+5680 where t is years after 1995. To find the total average credit card debt in the year 2027, we must first find the difference in years between 2027 and 1995 to get our t value. To do this subtract 1995 from 2027: t= 2027 - 1995 = 32 years. Next, we plug in 32 for t into the equation and solve for D: D = (393)*(32) + 5680 = $18,256.</span>

8 0

3 years ago