Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Your correct. It is what you put down
Answer:
x = 14
y = 7
z = 22
Step-by-step explanation:
x = # of cucumbers
y = # zucchini
z = # tomatoes
x + y + z = 43
2y = x or y = x/2
x + 8 = z
x + x/2 + x + 8 = 43
2x + x/2 = 35
4x + x = 70
5x = 70
x = 14
2y = 14
y = 7
14 + 8 = z
z = 22
Check if these variables are right:
14 + 7 + 22 = 43 ✔️
