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fgiga [73]
3 years ago
10

Which of the following equation has a graph that has a y-intercept of 4 and is parallel to 3y-9x=24?

Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

a

Step-by-step explanation:

in y intercept x = 0 so the choice a become the answer

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Square root of 75 plus square root of 3
olya-2409 [2.1K]
Answer:
6√3

Explanation:
Before we begin, remember the following:
\sqrt{a*b} = \sqrt{a}  *  \sqrt{b}
m \sqrt{a} + n \sqrt{a}  = (m+n) \sqrt{a}

Now, for the given:
75 can be written as 25*3
This means that:
\sqrt{75} = \sqrt{25*3}
Applying the above concept, we can find that:
\sqrt{75} = \sqrt{25*3} = \sqrt{25}  *  \sqrt{3}
Now, we know that:
√25 = 5 (we ignored the negative value)

This means that:
√75 = 5√3

Finally, we can compute the needed sum as follows:
√75 + √3 = 5√3 + √3 = 6√3

Hope this helps :)

8 0
3 years ago
Read 2 more answers
Suppose that g(x) = f(x) + 2. Which statement best compares the graph of
Xelga [282]

Answer:

Step-by-step explanation:

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a. clockwise b. Anticlockwise c. Straight

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a. Geogebra b. Kalzium c. Ghemical

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a. PhET b. PHET c. PheT

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8 0
3 years ago
Please help, last unit of algebra 2, thankyou!!!!!!!!!!!!​
Mumz [18]

Answer:

\cot \theta =  \frac{8}{15} \\\\\sec \theta =  \frac{17}{8} \\\\\csc \theta =  \frac{17}{15}

Step-by-step explanation:

\huge \tan \theta =  \frac{15}{8} ...(given) \\  \\  \huge \because \:  \cot \theta =  \frac{1}{ \tan \theta} \\  \\  \huge \therefore \: \cot \theta =  \frac{1}{ \frac{18}{8} } \\  \\  \huge \therefore \:  \cot \theta =  \frac{8}{15}  \\  \\ also \\ \huge  \sec \theta =  \frac{17}{8}  \\

6 0
3 years ago
What are three academic challenges yall 7th graders face?​
Musya8 [376]

Answer:

I'm not in 7th grade but 7th grade was not the year for me lol

Step-by-step explanation:

sh. it was wild XD

7 0
3 years ago
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12^0 + (1.25 x 4 +3 ) ( 1/2)^3 =
masya89 [10]

Answer:

2

Step-by-step explanation:

(12^0) + (((1.25 x 4) + 3) * ((1/2)^3)) = 2

hope this helps! :)

4 0
3 years ago
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