Answer:
be the second player, and always leave a multiple of 3 balloons
Step-by-step explanation:
In order to win, a player must force the other player to leave one or two balloons. To do that, the winning player must leave one more balloon than the maximum number that can be popped. That is, the winner will be the player who leaves 3 balloons,
Working backward, we find that the winner must leave a multiple of 3 after each turn. Since the starting number is a multiple of 3, the first player must lose if the second player plays optimally.
The winning strategy is ...
- be the second player
- always leave a multiple of 3 balloons.
While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that a digit in the ten thousand place values ten times what the same digit values is it is the thousand place.
It's not specified whether 1 is the 1st or 2nd roll: HOWER:
The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),} = 6
the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:
P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2
NOW if the 2nd Roll is "1", it 's still 1/2
well from my understanding of the problem and calculations i would say.. (-5.5,0)
Let s be standard and h be high-quality versions of the song.
To figure this out, let's make a system of equations:
2.5s + 4.5h = 5740
h = 4s
First substitute the second equation into the first for h.
2.5s + 18s =5740
Then combine like terms.
20.5s = 5740
Lastly, divide each side by 20.5 to get the number of standard downloads:
s = 280
Hope this helps!
