Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
21
Step-by-step explanation:
Let x be the amount of ticket for each game
Given
The expression 8x + 62 represents the total cost of the football game
The total coat for the.game will be
8(7)+62
= 56+62
= 118
If 9x + 34 represents the total cost of the baseball game. The total coat will be;
9(7)+34
= 63+34
=97
To know how much more football game costs, we will take the difference in their cost.
Difference = 118-97
Difference= 21
Hence football game costs 21 more than baseball
If the relationship between two quantities is a proportional relationship, this relationship can be represented by the graph of a straight line through the origin with a slope equal to the unit rate.
Answer:
see explanation
Step-by-step explanation:
Simplify the radical
= 
= 
Square both sides
T² = ( multiply both sides by (g + f) )
T²(g + f) = Ufg ( distribute left side )
T²g + T²f = Ufg ← subtract Ufg from both sides
T²g - Ufg + T²f = 0 ← subtract T²f from both sides
T²g - Ufg = - T²f ← factor out g from each term on the left side
g(T² - Uf) = - T²f ← divide both sides by (T² - Uf)
g = - 
= 
