Question

A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?

Answer 1

Answer:

x - 6

Step-by-step explanation:

A = x² - 11x + 30

= x² - 5x - 6x + 30

= x(x - 5) - 6(x - 5)

= (x - 6)(x - 5)

A = L x W

W = A/L

= (x - 6)(x - 5)/(x - 5)

= (x - 6)

Answer 2

Answer:

x - 6

Step-by-step explanation:

A = L x W

A / L = W

x^2-11x+30 / x -5  = W (Simplify the numerator)

(x - 6) x ( x - 5) / x - 5  = W     (Cancel the similar ones which is (x - 5) )

x - 6 = W

Hope that helps