3 years ago

A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?

Mathematics

2 answers:

Keith_Richards [23]3 years ago

5 0

Answer:

x - 6

Step-by-step explanation:

A = x² - 11x + 30

= x² - 5x - 6x + 30

= x(x - 5) - 6(x - 5)

= (x - 6)(x - 5)

A = L x W

W = A/L

= (x - 6)(x - 5)/(x - 5)

= (x - 6)

olya-2409 [2.1K]3 years ago

3 0

Answer:

x - 6

Step-by-step explanation:

A = L x W

A / L = W

x^2-11x+30 / x -5 = W (Simplify the numerator)

(x - 6) x ( x - 5) / x - 5 = W (Cancel the similar ones which is (x - 5) )

x - 6 = W

Hope that helps

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