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Ivan
3 years ago
10

A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?

Mathematics
2 answers:
Keith_Richards [23]3 years ago
5 0

Answer:

x - 6

Step-by-step explanation:

A = x² - 11x + 30

= x² - 5x - 6x + 30

= x(x - 5) - 6(x - 5)

= (x - 6)(x - 5)

A = L x W

W = A/L

= (x - 6)(x - 5)/(x - 5)

= (x - 6)

olya-2409 [2.1K]3 years ago
3 0

Answer:

x - 6

Step-by-step explanation:

A = L x W

A / L = W

x^2-11x+30 / x -5  = W (Simplify the numerator)

(x - 6) x ( x - 5) / x - 5  = W     (Cancel the similar ones which is (x - 5) )

x - 6 = W

Hope that helps

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we can make it easier by simplifying what we can

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7 0
3 years ago
How many 1/ 4-inch cubes does it take to fill a box with width 2 1/ 4 inches, length 2 1/ 2 inches, and height 1 3/ 4 inches?
lys-0071 [83]

Answer:

630.

Step-by-step explanation:

<u>Given the following data;</u>

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Volume = 1/64 cubic inches.

For rectangular box;

Length = 2½ = 5/2 inches.

Width = 2¼ = 9/4 inches.

Height = 1¾ = 7/4 inches.

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Substituting into the equation, we have;

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6 0
3 years ago
Read 2 more answers
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soldi70 [24.7K]

Answer:

Step-by-step explanation:

To find the population variance, we first need the mean:

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(4-7.2)^2=10.24\\(6-7.2)^2=1.44\\(8-7.2)^2=.64\\(9-7.2)^2=3.24\\(9-7.2)^2=3.24

Add together those numbers and divide them by 5:

\sigma=\frac{10.24+1.44+.64+3.24+3.24}{5}=\frac{18.8}{5}=3.76

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