A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?
2 answers:
Answer:
x - 6
Step-by-step explanation:
A = x² - 11x + 30
= x² - 5x - 6x + 30
= x(x - 5) - 6(x - 5)
= (x - 6)(x - 5)
A = L x W
W = A/L
= (x - 6)(x - 5)/(x - 5)
= (x - 6)
Answer:
x - 6
Step-by-step explanation:
A = L x W
A / L = W
x^2-11x+30 / x -5 = W (Simplify the numerator)
(x - 6) x ( x - 5) / x - 5 = W (Cancel the similar ones which is (x - 5) )
x - 6 = W
Hope that helps
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<u><em>Hope this helps!!</em></u>
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