Which equation matches the graph?

Erin has written three tests for her math class. She calculates the average of hermarks on the first two tests. This average is

asambeis [7]

To obtain an overall average of 86%, a score of 96 is required on her 4th test.

Let the required score on her fourth test = t

The required average = 86%

Initial scores : 80% + 83.5% + 84.5%

Average = ΣX/ (fx)

fx = total score obtainable = 4 × 100 = 400

ΣX = sum of scores

Average = 86%

0.86 = ((80 + 83.5 + 84.5 + t) / 400)

86 = (248 + t) / 400

400 × 0.86 = 248 + t

344 = 248 + t

344 - 248 = t

96 = t

In other to obtain an overall average of 86%, she has to score 96 in her 4th test.

Learn more : brainly.com/question/15528814

3 0

3 years ago

- 4/7 divided by 1 3/4

GarryVolchara [31]

Answer:

0.32653061224

Step-by-step explanation:

To write 0.32653061224 as a fraction you have to write 0.32653061224 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.32653061224 = 0.32653061224/1 = 3.2653061224/10 = 32.653061224/100 = 326.53061224/1000 = 3265.3061224/10000 = 32653.061224/100000 = 326530.61224/1000000 = 3265306.1224/10000000 = 32653061.224/100000000 = 326530612.24/1000000000 = 3265306122.4/10000000000 = 32653061224/100000000000

And finally we have:

0.32653061224 as a fraction equals 32653061224/100000000000

5 0

3 years ago

Has a slope of 2 and passing through (10, 17)

LUCKY_DIMON [66]

Answer:

y = 2x - 3

Step-by-step explanation:

The slope intercept form of a linear equation is y = mx + b

We know that m = 2

We can plug in x and y values to find b

17 = 2(10) +b

b = 17 - 20

b = -3

Therefore,

y = 2x - 3

4 0

3 years ago

A college student is moving into a campus dormitory. The student rents a moving truck for $19.95 plus $.99 per mile. Before retu

tiny-mole [99]

Answer:

60 miles

Step-by-step explanation:

you have to do 19.95+ .99x+ 65.32= 144.67

7 0

3 years ago

Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.

alina1380 [7]

Answer:

$v_1=(\frac{1}{10},-\frac{3}{10})$

$v_2=(-\frac{1}{10},\frac{3}{10})$

Step-by-step explanation:

First we define two generic vectors in our $\mathbb{R}^2$ space:

$v_1 = (x_1,y_1)$
$v_2 = (x_2,y_2)$

By definition we know that Euclidean norm on an 2-dimensional Euclidean space $\mathbb{R}^2$ is:

$\left \| v \right \|= \sqrt{x^2+y^2}$

Also we know that the inner product in $\mathbb{R}^2$ space is defined as:

$v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2$

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

$\left \| v_1 \right \|= \sqrt{x^2+y^2}=1$

and

$\left \| v_2 \right \|= \sqrt{x^2+y^2}=1$

As second condition we have that:

$v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0$

$v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0$

Which is the same:

$y_1=-3x_1\\y_2=-3x_2$

Replacing the second condition on the first condition we have:

$\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}$

Since $x_1^2= \frac{1}{10}$ we have two posible solutions, $x_1=\frac{1}{10}$ or $x_1=-\frac{1}{10}$ . If we choose $x_1=\frac{1}{10}$ , we can choose next the other solution for $x_2$ .

Remembering,

$y_1=-3x_1\\y_2=-3x_2$

The two vectors we are looking for are:

$v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})$

5 0

3 years ago