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Dahasolnce [82]
2 years ago
11

What is the equation of the trend line? Enter your answers in the boxes. K = _J +_

Mathematics
1 answer:
MrRissso [65]2 years ago
8 0
The y-intercept of the trend line is (0,28).  The slope of this line is
         28-0
m = --------- = 2
         14-0

Thus, the equation of the trend line, in variables K and J, is

K = 2J + 28
You might be interested in
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
2 years ago
Find the surface area of the composite figure. 6cm 5 cm 20cm 4cm 12cm 6cm​
Crazy boy [7]

Answer:

644 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the large rectangular prism + surface area of the small rectangular prism - 2(area of the surface of the small rectangular prism that joins the larger prism)

✔️Surface area of the large rectangular prism = 2(LW + LH + WH)

L = 6 cm

W = 5 cm

H = 20 cm

Surface area = 2(6*5 + 6*20 + 5*20)

= 500 cm²

✔️Surface area of the small rectangular prism = 2(LW + LH + WH)

L = 6 cm

W = 4 cm

H = 12 cm

Surface area = 2(6*4 + 6*12 + 4*12)

= 288 cm²

✔️area of the surface of the small rectangular prism that joins the larger prism = L*W

L = 12 cm

W = 6 cm

Area = 12*6

= 72 cm²

✅Surface area of the composite figure = 500 + 288 - 2(72)

= 644 cm²

7 0
2 years ago
30 points I'm struggling Find the equations of each line and show all of your work. (1, 5) (2, 6) (1, 1) (3, -8) (2, -3) (5, -2)
Free_Kalibri [48]

Answer:

1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b

5=1(1)+b 4=b

y=x+4

2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b

1=-9/2(1)+b b=11/2

y=-9/x+11/2

3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b

-3=1/3(2)+b -3=2/3+b

-3-2/3=b

 b=-11/3

y=1/3x-11/3

4.(2,5)and (4,3) m=-1 y=-1x+b

5=-1(2)+b 5=-2+b

5+2=b

b=7

y=-1x+7

6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b

-5=1(-3)+b -5=-3+b

-5+3=b

-2=b

y=1x-2

Step-by-step explanation:

7 0
2 years ago
Choose the equation below that represents the line passing through the point (1, −4) with a slope of one half . (1 point)
bixtya [17]
3rd one
Reason: 
Point slope formula: y-y1=m(x-x1) 
y1=-4
x1=1
m=1/2
Put it all together and you get a final answer of:
y-(-4)=1/2(x-1)
two negatives make one positive
so, 
final answer:y+4=1/2(x-1)
6 0
2 years ago
2/3 * 1/5 * 4/7 using cancellation
sergeinik [125]
I just want points but your answer is Modelo time
4 0
3 years ago
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