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Illusion [34]
3 years ago
14

Help me out please

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

The surface area of the geometric shape is B. 840 cm².

Step-by-step explanation:

Step 1:

The given figure is made up of three rectangles and two triangles.

The surface area of the geometric shape is given by summing the individual surface areas.

The geometric shape's surface area = The sum of the individual surface areas.

Step 2:

The surface area of the rectangles is the multiplication of its length and width.

The surface area of the rectangle with length z and width x = (26)(10)= 260 cm^{2}.

The surface area of the rectangle with length y and width x = (24)(10)= 240 cm^{2}.

The surface area of the rectangle with length x and width x = (10)(10)= 100 cm^{2}.

Step 3:

The area of a triangle is half the product of its base length and height.

The surface area of a triangle with base y and height x= \frac{1}{2} (24)(10) = 120 cm^{2}.

They are two similar triangles so their areas are equal

Step 4:

The geometric shape's surface area = 160 + 240+100+120+120 = 840 cm^{2}.

So the surface area is option B. 840 cm².

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Yo can someone please help and fast PLEASE
Illusion [34]

Answer:

It's incorrect because the equation is solve incorrectly the anwer is r= -4

Step-by-step explanation:

Add 4r4r to both sides.

-3r+9+4r=5

−3r+9+4r=5

2 Simplify  -3r+9+4r−3r+9+4r  to  r+9r+9.

r+9=5

r+9=5

3 Subtract 99 from both sides.

r=5-9

r=5−9

4 Simplify  5-95−9  to  -4−4.

r=-4

r=−4

6 0
3 years ago
PLEASE HELP ME I CANT FAIL
insens350 [35]
The correct answer is C


Explain

The graph is given

F(x) is given -2^x

By putting x= - 3 in the first equation
G(x) = -9

Which is false


by putting x= -3 in the second equation

g(x) is also equal -9

Which is false


Hope this help you :D
5 0
3 years ago
A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not
castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

<h3><u>Find P(B)</u></h3>

P(B) = \frac{8}{12}

<h3><u>Find P(B n R)</u></h3>

P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}

<h3><u>Find </u><u> P(R | B)</u></h3><h3>P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}</h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0
4 years ago
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
4 years ago
If x = 4 units, y = 4 units, and h = 6 units, the area of this trapezoid is
Jlenok [28]

Answer: the answer is 24

Step-by-step explanation:

5 0
3 years ago
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