Answer:
0.109 g.
Explanation:
Equation of the reaction:
Na3PO4 + 3HCl --> 3NaCl + H3PO4
Number of moles of HCl = molar concentration × volume
= 0.1 × 0.04
= 0.004 mol.
By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3
= 0.0013 mol
Mass of Na3PO4 = molar mass × number of moles
= 0.0013 × 164
= 0.219 g
Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance
= 0.219 × 50 g/100 g
= 0.109 g.
Which list of elements contains two metalloids?(1) Si, Ge, Po, Pb (3) Si, P, S, Cl(2) As, Bi, Br, Kr (4) Po, Sb, I, Xe
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The answer is (1). Si and Ge are both metalloids (semimetals)
If a student burns 3.53 moles of C3H8, 10.29 moles of carbon dioxide would be produced. Details about number of moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated as follows:
The following chemical equation was given as follows:
C3H8 + 502 = 3CO2 + 4H₂O
1 mole of C3H8 produced 3 moles of carbon dioxide
Hence, 3.53 moles of C3H8 will produce 3.53 × 3 = 10.59 moles of CO2.
Therefore, if a student burns 3.53 moles of C3H8, 10.29 moles of carbon dioxide would be produced.
Learn more about number of moles at: brainly.com/question/26416088
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