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2 years ago

Is this relation a function? {(3, 2), (5, 9), (11, 25)}

Mathematics

1 answer:

Mumz [18]2 years ago

4 0

Answer:

Yes

Step-by-step explanation:

None of the X values are the same number.

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How to simplify 3(x+2)

Rudik [331]

3(x + 2)
3(x) + 3(2)
3x + 6

3 0

2 years ago

I really need help on some questions can you help....

umka2103 [35]

Answer:

Step-by-step explanation:

The answer will be 20 because you are doubling from both sides.

3 0

2 years ago

a plane can fly 7 miles per minute. the plane will fly 8 trips, and each trip is 810 miles. how many hours will the plane fly? s

Gnesinka [82]

Answer: 12 hours and 24 Minutes

Step-by-step explanation:

7*60 = 420

810/420 = 1.9285

93- 100 = 53-60

subtract 40 from 93.

1.53*8 = 12.24

Answer: 12 hours and 24 Minutes

3 0

3 years ago

Tell whether the equation is true. Justify your answer. 24x3+(15-7)÷2=8x9+12÷2

Mashcka [7]

False
Because the left side comes out to a sum of 40 while 15-7 equals 8 and 24 times 3 equals 72 72 plus 8 equals 80 divided by 2 equals 40 and 8 times 9 equals 72 plus 6 equals 78 plus 6 equals 84

4 0

2 years ago

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

The question is

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

5 0

3 years ago