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2 years ago

7

What is the slope of the line that passes through the point (-4,-4)and (6,4)?

1 answer:

Arada [10]2 years ago

8 0

Answer:

slope = 0.8

Step-by-step explanation:

HOPE THIS HELPS :)

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58% of what is 63.4?

lesya [120]

109.31

To find this you can convert 58% to decimal form, which is .58. Once you have a decimal form of a percent, you can multiply it by the number you are taking the percent of and get an answer. So .58 times something equals 63.4. You can write this as an equation:

.58x = 63.4

and solve for x, which would get 63.4/.58, which equals 109.31.

8 0

3 years ago

What is greater, 2/3 or 7/8?

user100 [1]

$\frac{2}{3} = \frac{2 \times 8}{3 \times 8}=\frac{16}{24} \\ \\
\frac{7}{8}=\frac{7 \times 3}{8 \times 3}=\frac{21}{24} \\ \\
16$

7/8 is greater.

7 0

3 years ago

Read 2 more answers

Write the equation of the line, in slope-intercept form, with the

IrinaVladis [17]

Answer:

y = -x -1

Step-by-step explanation:

x1= 0, y1= -1

$slope = \frac{x - x1}{y - y1} = \frac{x - 0}{y - ( - 1)} = \frac{x}{y + 1}$

-1 = x/(y+1)

-1 (y+1) = x

y+1 = -x

y= -x -1

8 0

3 years ago

I am so lost, please help

skelet666 [1.2K]

Answer:

$u=\frac{9}{t}-\frac{1}{2} a t$

Step-by-step explanation:

Step 1: Given equation: $9=\frac{1}{2} a t^{2}+u t$

To get u, by subtraction equality property subtract both sides of the equation by $\frac{1}{2} a t^{2}$ .

$\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}$

$\Rightarrow 9-\frac{1}{2} a t^{2}=u t$

Step 2: By division equality property, divide both sides of the equation by t.

$\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}$

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$ .

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$ .

7 0

3 years ago

Bad White [126]

first polygon

ext. angle=180°-120°

=60°

$ext \: ang = \frac{360}{n}$

n=360°/60°

n=6

second polygon

n=2(6)=12

ext. ang= 360°/n = 360°/12° = 30°

int. ang = 180°-30°= 150°

answer is C

6 0

3 years ago