Question

A sample of tin (Cp = 0. 227 J/g•°C) is placed in a freezer. Its temperature decreases from 15. 0°C to â’10. 0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures. G.

Answer 1

Taking into account the definition of calorimetry, the mass of the sample is 478.41 grams.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

• Q= -543 J because the energy is releases
• c= 0.227 $\frac{J}{gC}$
• m= ?
• ΔT= Tfinal - Tinitial= 10 C - 15 C= -5 C

Replacing:

-543 J= 0.227 $\frac{J}{gC}$× m× (-5 C)

Solving:

$m=\frac{-543 J}{0.227 \frac{J}{gC}x(-5 C)}$

m=478.41 grams

In summary, the mass of the sample is 478.41 grams.

Learn more about calorimetry:

• brainly.com/question/11586486?referrer=searchResults
• brainly.com/question/24724338?referrer=searchResults