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patriot [66]
2 years ago
15

What is a fibrous root?

Chemistry
2 answers:
marysya [2.9K]2 years ago
7 0
Fibrous roots are made up of many other small roots, they tend to grow out in many different directions from base to the stem.
Maslowich2 years ago
5 0
I don’t really know
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How many moles are in 16.94g of water?
alexira [117]

16.94/18=.9411111

sig figs: 0.9411 mole of water

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1,500 grams is equal to:<br> 1.5 kg<br> 1.5L<br> 1.5 cm<br> all of the above
Salsk061 [2.6K]
1kg is 1,000 grams plus .5 is 1.5 kg
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In reaction a, each sodium atom gives one electron to a chlorine atom in reaction be an isotope of oxygen decays to form an isot
aalyn [17]

Answer:

Exthermal heat, i think

Explanation:

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Which states of matter only appear in the hydrosphere
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2 years ago
What is the molarity of 225 grams of Cu(NO2)2 in a total volume of 2.59 L?
Kay [80]

Answer:

The molarity is 0.56\frac{moles}{L}

Explanation:

In a mixture, the chemical present in the greatest amount is called a solvent, while the other components are called solutes. Then, the molarity or molar concentration is the number of moles of solute per liter of solution.

In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by:

Molarity (M)=\frac{number of moles of solute}{Volume}

Molarity is expressed in units (\frac{moles}{liter}).

Then you must know the number of moles of Cu(NO₂)₂. For that it is necessary to know the molar mass. Being:

  • Cu: 63.54 g/mol
  • N: 14 g/mol
  • O: 16 g/mol

the molar mass of Cu(NO₂)₂ is:

Cu(NO₂)₂= 63.54 g/mol + 2*(14 g/mol + 2* 16 g/mol)= 155.54 g/mol

Now the following rule of three applies: if 155.54 g are in 1 mole of the compound, 225 g in how many moles are they?

moles=\frac{225 g*1 mole}{155.54 g}

moles= 1.45

So you know:

  • number of moles of solute= 1.45 moles
  • volume=2.59 L

Replacing in the definition of molarity:

Molarity=\frac{1.45 moles}{2.59 L}

Molarity= 0.56\frac{moles}{L}

<u><em>The molarity is 0.56</em></u>\frac{moles}{L}<u><em></em></u>

5 0
3 years ago
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