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Troyanec [42]
2 years ago
11

Write an equation of the line, in standard form, containing the points (−6, 19) and (−15, 28).

Mathematics
1 answer:
Rudiy272 years ago
7 0

The equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13

<em><u>Recall:</u></em>

  • Equation of a line can be written in standard from as Ax + By = C, where Ax and By are all terms of variable x and y, and C is a constant.
  • The equation of a line in point-slope, y - y_1 = m(x - x_1), can be rewritten in the standard form.
  • Slope (m) = \frac{y_2 - y_1}{x_2 - x_1}

Given: (−6, 19) and (−15, 28)

<em>Find the </em><em>slope </em><em>(m):</em>

<em />m = \frac{28 - 19}{-15 -(-6)} = \frac{9}{-9} = -1

Write the equation in point-slope form by substituting m = -1 and (x_1, y_1) = (-6, 19) into y - y_1 = m(x - x_1).

y - 19 = -1(x - (-6))\\\\y - 19 = -1(x + 6)

  • Rewrite in standard form

y - 19 = -1(x + 6)\\\\y - 19 = -x - 6\\\\y = -x - 6 + 19\\\\y = -x + 13\\\\\mathbf{x + y = 13}

Therefore, the equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13

Learn more about equation of a line in standard form on:

brainly.com/question/19169731

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