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3 years ago

A concrete patio is 5 2/3 feet wide. It has an area of 36 5/6 square feet. What is the length of the concrete patio

Mathematics

1 answer:

Aneli [31]3 years ago

4 0

The length of the concrete patio is 6 1/2.
I got this answer by dividing 36 5/6 and 5 2/3. Therefore, answer is 6 1/2

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

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3 years ago

Work out the value of each expression, when r= 2.5 and t = 6.

Usimov [2.4K]

Answer:

a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14

b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5

c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16

d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16

e) cannot decipher the equation

f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21

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2 years ago

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Factor of 169 and 9 squared

emmasim [6.3K]

Answer:

The greatest common factor of 169 and 81 is 1.

Step-by-step explanation:

9 squared is 81 and the greatest common factor of 169 and 81 is one. They have no other common factors. Please mark me brainliest and I hope this helps!

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