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Serjik [45]
3 years ago
8

How would you round the number 9.9813 x 10-5 to two significant figures? Group of answer choices 10 1.0 x 10-4 10.0 x 10-5 9.9 x

10-5
Mathematics
1 answer:
zaharov [31]3 years ago
8 0

Answer:

This Significant Figures Rounding Calculator rounds a given number to the amount of significant digits that you specify. This rounding number which you specify cannot be a negative number and it must be greater than 0. A number with 0 significant digits would be 0.

Step-by-step explanation:

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Prove the following
fomenos

Answer:

Step-by-step explanation:

\large\underline{\sf{Solution-}}

<h2 /><h2><u>Consider</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \dfrac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \}cos(23π+x)cos(2π+x)

<h2><u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) = sinx

\rm \: {cos \: (2\pi + x) }

\rm \: \cot \bigg( \dfrac{3\pi}{2} - x \bigg) \: = \: tanx

\rm \: cot(2\pi + x) \: = \: cotx

So, on substituting all these values, we get

\rm \: = \: sinx \: cosx \: (tanx \: + \: cotx)

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{sinx}{cosx} + \dfrac{cosx}{sinx}

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{ {sin}^{2}x + {cos}^{2}x}{cosx \: sinx}

\rm \: = \: 1=1

<h2>Hence,</h2>

\boxed{\tt{ \cos \bigg( \frac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \frac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \} = 1}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>ADDITIONAL INFORMATION :-</h2>

Sign of Trigonometric ratios in Quadrants

  • sin (90°-θ)  =  cos θ
  • cos (90°-θ)  =  sin θ
  • tan (90°-θ)  =  cot θ
  • csc (90°-θ)  =  sec θ
  • sec (90°-θ)  =  csc θ
  • cot (90°-θ)  =  tan θ
  • sin (90°+θ)  =  cos θ
  • cos (90°+θ)  =  -sin θ
  • tan (90°+θ)  =  -cot θ
  • csc (90°+θ)  =  sec θ
  • sec (90°+θ)  =  -csc θ
  • cot (90°+θ)  =  -tan θ
  • sin (180°-θ)  =  sin θ
  • cos (180°-θ)  =  -cos θ
  • tan (180°-θ)  =  -tan θ
  • csc (180°-θ)  =  csc θ
  • sec (180°-θ)  =  -sec θ
  • cot (180°-θ)  =  -cot θ
  • sin (180°+θ)  =  -sin θ
  • cos (180°+θ)  =  -cos θ
  • tan (180°+θ)  =  tan θ
  • csc (180°+θ)  =  -csc θ
  • sec (180°+θ)  =  -sec θ
  • cot (180°+θ)  =  cot θ
  • sin (270°-θ)  =  -cos θ
  • cos (270°-θ)  =  -sin θ
  • tan (270°-θ)  =  cot θ
  • csc (270°-θ)  =  -sec θ
  • sec (270°-θ)  =  -csc θ
  • cot (270°-θ)  =  tan θ
  • sin (270°+θ)  =  -cos θ
  • cos (270°+θ)  =  sin θ
  • tan (270°+θ)  =  -cot θ
  • csc (270°+θ)  =  -sec θ
  • sec (270°+θ)  =  cos θ
  • cot (270°+θ)  =  -tan θ
7 0
3 years ago
Read 2 more answers
7n+2 = 4n+17 solve the equation
lions [1.4K]

Answer:

n = -5

Step-by-step explanation:

Solve for n:

n + 2 = 4 n + 17

Hint: | Move terms with n to the left hand side.

Subtract 4 n from both sides:

(n - 4 n) + 2 = (4 n - 4 n) + 17

Hint: | Combine like terms in n - 4 n.

n - 4 n = -3 n:

-3 n + 2 = (4 n - 4 n) + 17

Hint: | Look for the difference of two identical terms.

4 n - 4 n = 0:

2 - 3 n = 17

Hint: | Isolate terms with n to the left hand side.

Subtract 2 from both sides:

(2 - 2) - 3 n = 17 - 2

Hint: | Look for the difference of two identical terms.

2 - 2 = 0:

-3 n = 17 - 2

Hint: | Evaluate 17 - 2.

17 - 2 = 15:

-3 n = 15

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -3 n = 15 by -3:

(-3 n)/(-3) = 15/(-3)

Hint: | Any nonzero number divided by itself is one.

(-3)/(-3) = 1:

n = 15/(-3)

Hint: | Reduce 15/(-3) to lowest terms. Start by finding the GCD of 15 and -3.

The gcd of 15 and -3 is 3, so 15/(-3) = (3×5)/(3 (-1)) = 3/3×5/(-1) = 5/(-1):

n = 5/(-1)

Hint: | Simplify the sign of 5/(-1).

Multiply numerator and denominator of 5/(-1) by -1:

Answer: n = -5

5 0
3 years ago
Find the degree of the polynomial: a^3+3a^2−5a
emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

a^3+3a^2-5a

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial   is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

a^3+3a^2- 5a

The terms are

a^3

3a^2

5a

The term  a^3 has  the largest exponent of  3

Note:  The degree of the polynomial does not depend  on coefficients of the terms

3 0
3 years ago
The city park in which Allen plays is a square and measures exactly one million square feet. Which side dimensions produce the m
valentina_108 [34]
A- 998.8×997.7=996502.76
B- 998.84×997.73=996572.6332
C- 998.843×997.731=996576.6252
D - 999×998=997002

So D is the answer
4 0
3 years ago
Select all the ordered pairs that satisfy the function y = 3x -4.
aksik [14]

Answer:

B and D

Step-by-step explanation:

plug in the x and y for the x and y in the equation

if the two sides come out equal to eachother they satify the function

if they dont well they dont satisfy the function

hope this helps <3

4 0
3 years ago
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